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Stels [109]
3 years ago
10

The length of the rectangle is 7/(x-4) feet, while its width is 5/x feet. Find its perimeter. Please help asap!!!!! :(

Mathematics
1 answer:
damaskus [11]3 years ago
3 0

The perimeter would be (24x - 40)/(x^2 - 4x).

In order to find this, first double the length and width as you would to find any perimeter.

7/(x - 4) * 2 = 14/(x - 4)

5/x * 2 = 10/x

Now to add those together, we need to give them common denominators. In order to do that with the first one, we need to multiply by x/x

14/(x - 14) * x/x = 14x/(x^2 - 14x)

Then we can do the same with the second part by multiplying by (x - 4)/(x - 4)

10/x * (x - 4)/(x - 4) = (10x - 40)/(x^2 - 14x)

Now we can add the two together

14x/(x^2 - 14x) + (10x - 40)/(x^2 - 14x) = (24x - 40)/(x^2 - 14x)

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3 0
3 years ago
Divide. 5/7 ÷ 3<br><br> Express the answer in simplest terms.
vlada-n [284]

Divide:


\frac{5}{7} : 3 = \frac{5}{7} x \frac{1}{3} = \frac{5x1}{7x3} = \frac{5}{21}



To divide one fraction by another, invert (turn upside-down) the second fraction, then multiply.


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Two solutions of different concentrations of acid are mixed creating 40 mL of a solution that is 32% acid. One-quarter of the so
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