The best way to solve a problem like this is to set up two equations. First assign a variable to each thing you are trying to find. In this case, it's two different kinds of cars. Let's call the cars that weigh 3,000 pounds x, and the ones that weigh 5,000 y. The two equations you should write are:
x+y=18 (because the problem tells you there were 18 cars in total)
3000x+5000y=60000 (because that is the total weight in the problem)
Next, you need to solve for one of the variables. I will solve for x first by subtracting y from both sides of the first equation.
x=18-y
Then you have to plug that into the other equation to get:
3000(18-y)+5000y=60000
Simplify and solve for y:
54000-3000y+5000y=60000
54000+2000y=60000
2000y=6000
y=3
Now that you know what y equals, you can put it into the equation we solved for x:
x=18-3
x=15
So there are 15 cars that weigh 3000 pounds and 3 that weigh 5000.
It would prolly be (b=-1.6).
That would be B because 65 < 40 + 30
Answer:
g(f(3)) = 0
Step-by-step explanation:
f(x) = 2x - 9
f(3) = 2(3) - 9
f(3) = -3
g(-3) = 9 - (-3)^2
g(-3) = 9 - 9
g(-3) = 0
In this problem, we are asked to give an expression that can be used to mentally multiply 6 and 198. In order not to go through the rigorous multiplication, we can estimate 198 to 200, that is 6 *200 equal to 1200. Since there is a 2*6 excess or 12 then we subtract: 1200 -12 equal to 1188.
