Based on the percentage of readers who own a particular make of the car and the random sample, we can infer that there is sufficient evidence at a 0.02 level to support the executive claim.
<h3>What is the evidence to support the executive's claim?</h3>
The hypothesis is:
Null hypothesis : P = 0.55
Alternate hypothesis : P ≠ 0.55
We then need to find the test statistic:
= (Probability found by marketing executive - Probability from publisher) / √( (Probability from publisher x (1 - Probability from publisher))/ number of people sampled
= (0.46 - 0.55) / √(( 0.55 x ( 1 - 0.55)) / 200
= -2.56
Using this z value as the test statistic, perform a two-tailed test to show:
= P( Z < -2.56) + P(Z > 2.56)
= 0.0052 + 0.0052
= 0.0104
The p-value is 0.0104 which is less than the significance level of 0.02. This means that we reject the null hypothesis.
The Marketing executive was correct.
Find out more on the null and alternate hypothesis at brainly.com/question/25263462
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Answer:
Selective retention.
Explanation:
Selective retention occurs when a person more easily remembers things that are closer to their beliefs, values, and Interests than things that are not.
Luis does not want to do his shopping at big box stores but prefers to shop locally. So when he reads about one of the big box stores (which is not his preference) is doing a big sale next week, he does not remember it because it is not consistent with what he wants. This is an example of selective retention.
Answer:
(c) Circle graph
Explanation:
The circle graph or pie chart is commonly used when we want to give a visual demonstration of the proportional division of a data. Each item is expressed as a sector of the circle where the angle is relative to the value of the item.
Answer: Net Asset Value = 1950
Explanation:
Assets = $225 million
Liabilities = $30 million
Shares outstanding = 10 million
We can compute the Net Asset Value, using the following formula:
<em>
</em>
<em>
</em>
<em>NAV per share = 19.5</em>
<em>Therefore, the NAV of 100 share is 1950</em>
