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Brilliant_brown [7]
2 years ago
13

If you were constructing a 99% confidence interval of the population mean based on a sample of n 1) = 25 where the standard devi

ation of the sample S = 0.05, the critical value of t will be
Mathematics
1 answer:
svetlana [45]2 years ago
3 0

Answer:

We want a confidence of 99% so then the significance level would be 1%

The degrees of freedom are given by:

df = n-1= 25-1=24

And the critical value using the significance level \alpha=0.01 and \alpha/2 =0.005 and the critical value would be:

t_{\alpha/2}= \pm 2.797

Step-by-step explanation:

We know the following info :

s= 0.05 represent the standard deviation from the sample

n = 25 represent the sample size selected

We want a confidence of 99% so then the significance level would be 1%

The degrees of freedom are given by:

df = n-1= 25-1=24

And the critical value using the significance level \alpha=0.01 and \alpha/2 =0.005 and the critical value would be:

t_{\alpha/2}= \pm 2.797

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