My guess would be A, but I may be wrong
Answer:
This information tells me that f equals a number and 3 multiplied by the number that f equals is 16.
<u><em>Could I please have Brainliest?</em></u>
Answer: Here is the complete table, with the filled in values:
______________________________________________________________
Time (h) Distance (mi)
3 2
9 6
12 8
18 12
___________________________________________________
Explanation:
___________________________________________________
Let us begin by obtaining the "?" value; that is, the "distance" (in "mi.") ;
when the time (in "h") is "18" ;
___________________________________________________
12/8 = 18/?
Note: "12/8 = (12÷4) / (8÷4) = 3/2 ;
Rewrite: 3/2 = 18/? ; cross-multiply: 3*? = 2 * 18 ;
3*? = 36 ;
Divide each side by "3" ;
The "?" = 36/3 = 12 ;
So, 12/8 = 18/12 ;
The value: "12" takes the place for the "?" in the table for "distance (in "mi.);
when the "time" (in "h") is "18".
__________________________________________________________
Now, let us obtain the "? " value for the "distance" (in "mi.");
when the "time" (in "h") is: "9" .
12/8 = 9/? ; Solve for "?" ;
We know (see aforementioned) that "12/8 = 3/2" ;
So, we can rewrite: 3/2 = 9/? ; Solve for "?" ;
Cross-multiply: 3* ? = 2* 9 ; 3* ? = 18 ;
Divide each side by "3" ;
to get: "6" for the "?" value.
When the time (in "h") is "9", the distance (in "mi.") is "6" .
____________________________________________________
Now, to solve the final "?" value in the table given.
9/6 = ?/2 ; Note: We get the "6" from our "calculated value" (see above problem).
9/6 = (9÷3) / (6÷3) = 3/2 ;
So, we know that the "?" value is: "3" .
Alternately: 9/6 = ?/2 ;
Cross-multiply: 6*? = 2*9 ; 6 * ? = 18 ; Divide each side by "6" ;
to find the value for the "?" ;
"?" = 18/6 = "3" .
When the "distance" (in "mi.") is: "2" ; the time (in "h") is: "3" .
____________________________________________________
Here is the complete table—with all the values filled in:
____________________________________________________
<span>Time (h) Distance (mi)
____________________________________________________
3 2
9 6
12 8
18 12
____________________________________________________</span>
Answer: We have
f'(x) = a x + b,
f'(x) = 0 at x = -b/a
f(x) = a x^2 / 2 + b x + c
Meaning of marked part
❟ ∵ a<0 ❟ f is a quadratic function
∴ f has absolute maximum value at x = -b/a
For all a with a less than zero, f is a quadratic function. Therefore f has a global maximum at x = -b/a
That typesetting seems very sloppy. It probably is supposed to be
∀a < 0, f is a quadratic function.
The second sentence is sloppy in use of "absolute". It can't mean absolute value, so presumably it means "global".
Sometimes a minimum or maximum is only local, but a quadratic function has exactly one extrema, and it is global. And if a < 0, the extrema is a global maximum.
Step-by-step explanation:
An extrema (minimum or maximum) for f(x) occurs only where f'(x) = 0, that is, when the slope of the tangent at x is zero.
But if the function crosses its tangent at that point, the point is an inflection point, not an extrema. A quadratic never crosses it's tangent.
Answer: 249 m^2
Step-by-step explanation:
