Convert 3 1/3 into a improper fraction:
= 10/3

Then flip the other fraction around and multiply them together:
1/3 -> 3/1
(10*3)/(3*1) = 30/3 = (30/3)/(3/3) = 10/1 = 10

The answer is 10

4 0

4 years ago

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A person on tour has dollar 360 for his daily expenses. If he extends his tour for 4 days, he has to cut down his daily expenses

Greeley [361]

Answer:

The original duration of the tour is 18 days.

Step-by-step explanation:

Let

the number of days spent be T

Daily expenses be D

Initially ,

total tour expenses was 360

$D \times T=360$

$D = \frac{360}{T}$ -------------(1)

If he extends his tour for 4 days, he has to cut down his daily expenses by dollar 3

$(D + 4) \cdot(T -3) = 360$ ---------------(2)

Expanding the eqaution(2)

DT-3D + 4T -12 = 360

Substituting the value of D

$(\frac{360}{T})T -3( \frac{360}{T}) + 4T -12 = 360$

$(\frac{360}{T})T -3( \frac{360}{T}) + 4T= 360 + 12$

$(\frac{360}{T})T -3( \frac{360}{T}) + 4T= 372$

$360 - ( \frac{1080}{T}) + 4T= 372$

$( \frac{1080}{T}) + 4T= 372 - 360$

$( \frac{1080}{T}) + 4T= 12$

$1080 + 4T^2= 12T$

Solving the quadratic equation we get

T = 18 and T = -15

T is the number of gays and it cannot be negative , hence T is 18

Substituting in equation (1) we get

$D = \frac{360}{18}$

D = 20

4 0

3 years ago

There are 24 boys and 16 girls in a hall, each holding coins in their hand.

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

total=average ×no.

18×40=720 the no. of coins for all children

12×24=288 no. of coins for boys

720-288=432 for all girls

one girl, mean,divide 432 by 16= 27

5 0

3 years ago