The answer is c.
csfwdwdfqffqsdqd
Step-by-step explanation:
the area of a rectangle is
length × width
in our case
length × width = 70 m²
length = 3×width - 11
we can use this second equation in the first and get
(3×width - 11) × width = 70
3×width² - 11×width - 70 = 0
the general solution to a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
a = 3
b = -11
c = -70
x = (11 ± sqrt((-11)² - 4×3×-70))/(2×3) =
= (11 ± sqrt(121 + 840))/6 =
= (11 ± sqrt(961))/6
x1 = (11 + 31)/6 = 42/6 = 7
x2 = (11 - 31)/6 = -20/6 = -10/3
the negative solution is not applicable for a length in an object.
so, only x1 = 7 m is our solution.
the width of the rectangle is 7 m.
the length = 3×width - 11 = 3×7 - 11 = 21-11 = 10 m
Answer:
Graph 4
Step-by-step explanation:
Parallel lines have no solution to the system of equation. Graph 4 is a set of parallel lines, so they will never intersect.
Let's find the perimeter first by adding all the side lengths together. There are two missing side lengths, which we can find by taking the side opposite them and subtract the side behind the missing side from them.
I've attached a diagram showing how to find the side lengths.
Now let's add all the side lengths together: 4 cm + 8 cm + 8 cm + 2 cm + 4 cm + 6 cm = 32 cm
The perimeter of this figure is 32 cm.
---
To find the area we can divide this figure into 2 rectangles. On the second attached diagram, I've split the figure into two and labeled the length and width of each rectangle.
Area of a rectangle = length * width
Area of red labeled rectangle = 4 cm * 2 cm = 8 cm²
Area of yellow labeled rectangle = 8 cm * 4 cm = 32 cm²
Add the two areas together: 8 + 32 = 40
The area of the figure is 40 cm².