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ZanzabumX [31]
3 years ago
10

Miguel score 35 fewer points in second bowling game than his first game his total score for the two games was 395 how many point

s did he score in each game? (plz show step by step)
Mathematics
1 answer:
olga_2 [115]3 years ago
5 0
So, let's say he scored "a" points in his first game. and "b" on the second.

his second game's score "b", and it was 35 fewer points, so is b=a - 35.

we also know that the total score for both games was 395, thus

\bf \begin{cases}
a+\boxed{b}=395\\
a+\boxed{a-35}=395
\end{cases}
\\\\\\
2a-35=395\implies 2a=395+35\implies 2a=430\implies a=\cfrac{430}{2}
\\\\\\
a=215

how many did he score in the second game?  well, b = a - 35.
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Recipe use 4 cups of flour 1 1/4 cups of milk, how much milk needed for 2 cups of flour
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For every 4 stickers it costs 2$ so if I get 50 stickers how much money would I have spent?
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when loaded with iron rods a lorry has mass of 12000kg. if the mass of iron rods is there times that of the empty lorry . find t
siniylev [52]

Complete Question

When loaded with iron rods a lorry has mass of 12000kg. if the mass of iron rods is three times that of the empty lorry, find the mass of iron.

Answer:

3000kg

Step-by-step explanation:

Let us represent

Mass of lorry = x

Mass of iron rods = y

x + y = 12000kg..... Equation 1

x = 12000kg - y

We are told that:

If the mass of iron rods is three times that of the empty lorry, find the mass of iron.

x = 3y

We substitute 3y for x in Equation 1

x = 12000kg - y

3y = 12000kg - y

Collect like terms

3y + y = 12000kg

4y = 12000kg

Divide both sides by 4

y = 12000kg/4

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4 0
3 years ago
Paul recently purchased Wii Fit. Each day Wii Fit calculates a Wii Fit Age. Over the course of the past week (N = 7 days), his W
evablogger [386]

Answer:

a) [20.366, 31.834]

b) Since, The age of 35 years does not belongs to the calculated interval of 95% confidence interval (i.e [20.366, 31.834]).

Paul's age is significantly different from his Mean Wii Fit Age.

Step-by-step explanation:

Data provided:

Number of days i.e sample size, n = 7

Mean, μ = 26.1

Standard deviation, σ = 6.2

Degrees of freedom, df = n - 1 = 7 - 1 = 6

Confidence level = 95%,

Now,

For Confidence level of 95% , α = 1 - 0.95 = 0.05

\frac{\alpha}{2}=\frac{0.05}{2} = 0.025,

From the t stats table,

tc = t(α/2, df)

or

tc = t(0.025, 6) = 2.447

Therefore,

Margin of error = t\times\frac{\sigma}{\sqrt n}

or

Margin of error =2.447\times\frac{6.2}{\sqrt {7}}

or

Margin of error = 5.734

Therefore,

The 95% confidence interval = Mean ± Margin of error

or

The 95% confidence interval = [ (26.1 - 5.734) , (26.1 + 5.734)]

or

The 95% confidence interval = [20.366, 31.834]

b) Since, The age of 35 years does not belongs to the calculated interval of 95% confidence interval (i.e [20.366, 31.834]).

Therefore, it can be concluded that the Paul's age is significantly different from his Mean Wii Fit Age.

5 0
3 years ago
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