Answer: 1/5, 1/2, 0.
Step-by-step explanation:
given data:
no of cameras = 6
no of cameras defective = 3
no of cameras selected = 2
Let p(t):=P(X=t)
p(2)=m/n,
m=binomial(3,2)=3!/2!= 3
n=binomial(6,2)=6!/2!/4! = 15
p(3)= 3/15
= 1/5.
p(1)=m/n,
m=binomial(6,1)*binomial(2,2)=6!/1!/4!*2!/2!/0!= 7.5
n=binomial(6,2)= 15
p(2)= 7.5/15
= 1/2
p(0)=m/n,
m=0
p(0)=0
Answer:
There is no solution for this set of equations.
The sum of two numbers can not have two different solutions.
Answer:
2.090909...
Step-by-step explanation:
Write as improper fraction and then divide
23/11=2.090909...
Answer:
There are two ways you can write it. You can write it how you would casually say it:
Fifty and two (or Fifty point Two)
But mathematically, you would say it as:
Fifty and Two-tenths.
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Answer:
Step-by-step explanation:
because you put each thing to the power
