Question:
You are in a bike race. When you get to the first checkpoint, you are 2/5 of the distance to the second checkpoint. When you get to the second check point, you are 1/4 of the distance to the finish. If the entire race is 40 miles, what is the distance between the start and the first check point?
Answer: 4 miles
Step-by-step explanation:
Let distance between start to first checkpoint = x
First checkpoint to second checkpoint = 2/5 of x
Distance of start to checkpoint 1 = ( 2/5 of start to checkpoint 2)
Distance of start to checkpoint 2 = (1/4 of start to finish)
If start to checkpoint 2 = 1/4 of start to finish
Then,
Distance of start to checkpoint 1 = ( 2/5 * 1/4 of start to finish)
Distance of start to checkpoint 1 = 2/20 of start to finish = 1/10 of start to finish
Entire race = 40 miles = distance from start to finish
1/ 10 of 40
= ( 1/10) × 40
= 4 miles
An=a1(r)^(n-1)
a1=first term
r=common rati
common ratio is a term divded by previous term
6/3=2
r=2
first term is 3
an=3(2)^(n-1)
14th term
a14=3(2)^(14-1)
a14=3(2)^13
a14=3(8192)
a14=24576
the 14th term is 24576
Reflection across the y-axis
Answer: OWA OWA
Step-by-step explanation:
Answer:
5. I agree with your answer choice.
6. 13.3
Step-by-step explanation:
5. You have m∠1 = 90° = m∠2, so it is reasonable to invoke the transitive property. (Step 4 would use "angles with the same measure are congruent" to complete the proof.)
6. The difference in x-coordinates is (4-1) = 3. The difference in y-coordinates is (22-9) = 13. By the Pythagorean theorem, the distance between the points is ...
... √(3² +13²) = √178 ≈ 13.342 ≈ 13.3
