Question

2. The robot was initially placed at position (6,9), and at = 2 seconds, its position is (10,15).

Answer 1

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~ 6 &,& 9~) % (c,d) &&(~ 10 &,& 15~) \end{array}~~~ % distance value d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(10-6)^2+(15-9)^2}\implies d=\sqrt{4^2+6^2}\implies d=\sqrt{52} \\\\\\ d\approx 7.2$

what's its speed?  well, it traveled √(52) in 2 seconds, so is simply √(52)/2, which is about 3.6 units per second.