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Sunny_sXe [5.5K]
3 years ago
12

2. The robot was initially placed at position (6,9), and at = 2 seconds, its position is (10,15).

Mathematics
1 answer:
qaws [65]3 years ago
4 0
\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ 6 &,& 9~) 
%  (c,d)
&&(~ 10 &,& 15~)
\end{array}~~~ 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{(10-6)^2+(15-9)^2}\implies d=\sqrt{4^2+6^2}\implies d=\sqrt{52}
\\\\\\
d\approx 7.2

what's its speed?  well, it traveled √(52) in 2 seconds, so is simply √(52)/2, which is about 3.6 units per second.
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