Use Law of Cooling:

T0 = initial temperature, TA = ambient or final temperature
First solve for k using given info, T(3) = 42

Substituting k back into cooling equation gives:

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:

Solve for x:

Sub back into original cooling equation, x = T(t)

Solve for t:

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM
1. The mean of all the numbers is 41.
5. Median : 52
Answer:
-1
Step-by-step explanation:
Given,
f(x) = -x² + 4x - 1 and x = 0
Putting the value of x we get,
f(0)=
+ (4 X 0) - 1
= -0+0-1
=-1
∴f(x)= -1
So, the required value is -1
I have no idea. Quick question for you though since we are working on similar stuff. How do I write this equation in graphing form: y=2x^2-12x+19
So the ratios are 5:5 and 3:5 so the fractions are 5/10 (1/2) for 7th grade and 5/8 for 8th grade