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babunello [35]
3 years ago
9

A three-letter word used to show division in a word problem.

Mathematics
2 answers:
Grace [21]3 years ago
7 0
A three-letter word used to show division in a word problem is PER.
Juliette [100K]3 years ago
7 0
One word I remember being taught was "per". Hope that helps :)
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Organize the following polynomial expressions from least to greatest based on their degree:
bixtya [17]
The correct answer is 
III, I, II, IV
8a - 5
6x2
18x3 + 5ab - 6y
4x3y + 3x2 - xy - 4
7 0
3 years ago
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Write the expression in factored form. 81m^2-49
ivolga24 [154]
We can use the difference of two squares, which is:

x^2 + y^2 = (x-y)(x+y)

So,

(9m-7)(9m+7)

Hope this helps!
5 0
2 years ago
21 is 20% of what number
Ksenya-84 [330]

Answer:

21 is 20% of 105

Step-by-step explanation:

20% * x = 21

20/100 * x = 21

x = 21 * 100/20

x = 105

If you are using a calculator, simply enter 21×100÷20, which will give you the answer.

6 0
3 years ago
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Which properties are present in a table that represents an exponential function in the form y-b* when b > 1?
erastovalidia [21]

Answer:

<u>Properties that are present are </u>

Property I

Property IV

Step-by-step explanation:

The function given is  y=b^x  where b > 1

Let's take a function, for example,  y=2^x

Let's check the conditions:

I. As the x-values increase, the y-values increase.

Let's put some values:

y = 2 ^ 1

y = 2

and

y = 2 ^ 2

y = 4

So this is TRUE.

II. The point (1,0) exists in the table.

Let's put 1 into x and see if it gives us 0

y = 2 ^ 1

y = 2

So this is FALSE.

III. As the x-value increase, the y-value decrease.

We have already seen that as x increase, y also increase in part I.

So this is FALSE.

IV. as the x value decrease the y values decrease approaching a singular value.

THe exponential function of this form NEVER goes to 0 and is NEVER negative. So as x decreases, y also decrease and approached a value (that is 0) but never becomes 0.

This is TRUE.

Option I and Option IV are true.

3 0
3 years ago
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According to the Fundamental Theorem of Algebra, the graph of f(x) = x2 - 4x + 3, has roots. From the graph we can see that it h
andreyandreev [35.5K]

Answer:

The graph f(x)=x^2-4x+3  has two zeros namely 3 and 1.

Step-by-step explanation:

Consider the given equation of graph f(x)=x^2-4x+3

According to the Fundamental Theorem of Algebra

For a given polynomial of degree n can have a maximum of n roots.

Thus, for the given equation f(x)=x^2-4x+3  the degree of polynomial is 2 , thus the function can have maximum of 2 roots.

We know at roots the value of function is 0 that is f(x) = 0,

Substitute f(x) = 0 , we get, f(x)=x^2-4x+3=0

This is a quadratic equation, x^2-4x+3=0

We first solve it manually and then check by plotting graph.

Quadratic equation can be solved using middle term splitting method,

here, -4x can be written as -x-3x,

x^2-4x+3=0 \Rightarrow x^2-x-3x+3=0

\Rightarrow x(x-1)-3(x-1)=0

\Rightarrow (x-3)(x-1)=0

Using zero product property, a\cdot b=0 \Rightarrow a=0\ or \ b=0

\Rightarrow (x-3)=0 or \Rightarrow (x-1)=0

\Rightarrow x=3 or \Rightarrow x=1

Thus, the two zero of f(x) are 3 and 1.

We can also see on graph attached below that the graph f(x)=x^2-4x+3  has two zeros  namely 3 and 1.  

3 0
2 years ago
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