One weighs a pound and the other pounds away!
To find the probability that A occurs given B occurs, multiply the Probability of A by the probability of B.
3/4 x 5/8 = 15/32
<15> and <10> add first 25 <25> and 5 add second 30 <30> and 7 add third 37 <37> and 6 <6> now add that an u get <43> thats ur answer :)
Using the binomial distribution, there is a 0.3474 = 34.74% probability of getting one wrong number.
<h3>What is the binomial distribution formula?</h3>
The formula is:
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
For this problem, the values of the parameters are given by:
p = 0.15, n = 10.
The probability of getting one wrong number is P(X = 1), hence:
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
P(X = 1) = C(10,1) x (0.15)¹ x (0.85)^9 = 0.3474
0.3474 = 34.74% probability of getting one wrong number.
More can be learned about the binomial distribution at brainly.com/question/24863377
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18 for the first the second is 50 and 60