Answer:
3*sqrt(3x)
--------------
2x
Step-by-step explanation:
To rationalize the denominator, we need to get rid of the square root. We need to multiply by sqrt(12x)/sqrt(12x)
9 sqrt(12x)
---------- * -----------
sqrt(12x) sqrt(12x)
9sqrt(12x)
-----------------
12x
We can cancel 3 in the top and bottom
3sqrt(12x)
---------------
4x
We also notice that 12 is made up of 4 and 3
3sqrt(4) sqrt(3x)
---------------
4x
3sqrt(4) sqrt(3x)
----------------------
4x
3*2sqrt(3x)
--------------
4x
We can cancel a 2 in the top and bottom
3*sqrt(3x)
--------------
2x
There are 3 more dots above the 13 than are above the 12, so the appropriate choice is ...
... A. 3
Answer:
$16
Step-by-step explanation: I did the math in the comments.
Cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.
<u>Solution:
</u>
Need to calculate ![\sqrt[3]{1728}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1728%7D)
and then multiply the result by ![\sqrt[3]{14903}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B14903%7D)
Let us first evaluate
![\Rightarrow \sqrt[3]{1728}=\sqrt[3]{12 \times 12 \times 12}=12](https://tex.z-dn.net/?f=%5CRightarrow%20%5Csqrt%5B3%5D%7B1728%7D%3D%5Csqrt%5B3%5D%7B12%20%5Ctimes%2012%20%5Ctimes%2012%7D%3D12)
As need to multiply 12 by
![\Rightarrow 12 \times \sqrt[3]{14903}](https://tex.z-dn.net/?f=%5CRightarrow%2012%20%5Ctimes%20%5Csqrt%5B3%5D%7B14903%7D)
On solving , we get
![\sqrt[3]{14903}=24.608](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B14903%7D%3D24.608)
![\Rightarrow 12 \times \sqrt[3]{14903}=12 \times 24.608=295.306](https://tex.z-dn.net/?f=%5CRightarrow%2012%20%5Ctimes%20%5Csqrt%5B3%5D%7B14903%7D%3D12%20%5Ctimes%2024.608%3D295.306)
Hence cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.
Answer:
yes, your right
Step-by-step explanation:
