Let \[x_2=\{n\ | 1\leq n\leq 200, n=k^2\ \exists k\in \z\},\] \[x_3=\{n\ | \ 1\leq n\leq 200, n=k^3\ \exists k\in \z\},\] and \[
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Answer:
0.01083 or 1.083%
Step-by-step explanation:
This problem can be modeled as a binomial probability model with probability of success p = 0.56.
The probability of x=13 successes (a college student being very confident their major would lead to a good job) in a number of trials of n=15 is:
The probability is 0.01083 or 1.083%.