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3 years ago

Graph the equation below by plotting the y-intercept and a second point on the line. (Zoom in if blurry)

Mathematics

2 answers:

stira [4]3 years ago

6 0

Answer:

The coordinates I chose were (0,2) and (4,5)

Step-by-step explanation:

Didn't you already do this question?

zlopas [31]3 years ago

3 0

Answer:

2y and up 3 and over 2 bla bla bla

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Find the radius of the circle if the center is at (1, 2) and the point (-3, 4) lies on the circle.

Anton [14]

Answer:

2√5

Step-by-step explanation:

The radius is the distance from the center to a point anywhere along the edge of the circle. To find the distance between these two points, use the distance formula.

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(1--3)^2 + (2-4)^2}\\ d = \sqrt{4^2 + -2^2}\\ d = \sqrt{16 + 4}\\ d = \sqrt{20} \\d = 2\sqrt{5}$

7 0

4 years ago

Read 2 more answers

Which number represents the BASE?<br> 42=16<br> A. 4<br> B. 2<br> C. 16

stepladder [879]

Answer:

Step-by-step explanation:

6 0

3 years ago

Find the coordinates of a point on the directed segment from (-3,6) to (7,1) that divides it into a ratio of 3:1.

Masja [62]

Step-by-step explanation:

To divide a directed segment, we need to divide the length of the segment, along the x and the y directions separately. Then add the subdivided segment to the starting point of the directed segment (-3,6) to get the point of division.

Let the length be denoted by delta, then

delta = (7,1) - (-3,6) = (10,-5)

Multiply delta by the ratio of 3 / (3+1) = 3/4

(10,-5) * 3/4 = (7.5, -3.75)

Add the subdivided segment to the starting point:

(-3,6) + (7.5, -3.75) = (4.5, 2.25)

So the point of division is (4.5, 2.25)

4 0

3 years ago

Graph the inequality in the coordinate plane. y<5

Arisa [49]

Answer:

just graph 5 like usual.....

Step-by-step explanation:

8 0

3 years ago

Hi! I've tried this problem a couple times but am still stumped :( Can you help?!

aniked [119]

ANSWER:

$X\text{ = }\begin{bmatrix}{12} & {-4} & {-2} \\ {-8} & {-13} & {8} \\ {8} & {15} & {18}\end{bmatrix}$

EXPLANATION:

Given:

$U\text{ = }\begin{bmatrix}{1} & {3} & {-5} \\ {2} & {14} & {11} \\ {-8} & {0} & {5}\end{bmatrix}\text{ V =}\begin{bmatrix}{13} & {1} & {-7} \\ {-6} & {1} & {9} \\ {0} & {15} & {23}\end{bmatrix}$

Since U and V are Matrices with equal dimensions(3 x 3 matrix), and

X + U = V.

To solve for X, we have:

X = V - U

$\begin{gathered} X\text{ = V - U} \\ X\text{ = }\begin{bmatrix}{13-1} & {-1-3} & {-7-(-5)} \\ {-6-2} & {1-14} & {19-11} \\ {0-(-8)} & {15-0} & {23-5}\end{bmatrix}=\text{ }\begin{bmatrix}{12} & {-4} & {-2} \\ {-8} & {-13} & {8} \\ {8} & {15} & {18}\end{bmatrix} \end{gathered}$ $X\text{ = }\begin{bmatrix}{12} & {-4} & {-2} \\ {-8} & {-13} & {8} \\ {8} & {15} & {18}\end{bmatrix}$

6 0

1 year ago