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natita [175]
3 years ago
6

Solve the equation

Mathematics
1 answer:
12345 [234]3 years ago
3 0

Answer:

Step-by-step explanation:

x+(x+1)+(x+2)+(x+3)=-210

x+1x+1+1x+2+1x+3=-210

4x+6=-210

4x=-210-6

4x/4x=-216/4

x=54

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3) Tara sold candles to raise money for new playground equipment at her school.
Ronch [10]

Answer:

Tara's current expression finds how much the school will be keeping. 50 x 2/5 (also written as 50 x 0.4) totals out as 20. $20 is 2/5 of $50. The expression that Tara SHOULD have written to find how much goes to the candle company would be 50 x 3/5 (also written as 50 x 0.6), as this adds up to 30. $30 is 3/5 of $50.

Step-by-step explanation:

50/5 = 10 which means that 1/5 of 50 = 10.

2/5 of 50 ($20) is kept by the school. This is what Tara's expression finds. This means that $30 is sent to the candle company, and can be found with the expression 50 x 3/5.

The decimals are created by dividing the numerator of the fraction by the denominator (I find it easier to do math with decimals).

3 0
2 years ago
Evaluate the following expression. y + 9 when y = 12
tino4ka555 [31]

Answer:

21

Step-by-step explanation:

y+9 = ?

y=12

12+9=21

5 0
2 years ago
Read 2 more answers
Geometry help what is it will give brainliest
Lapatulllka [165]
For this problem, we can say that corresponding angles are congruent, or the same, this also means that their angle measures have to be the same. Then, our equations for our angles will be vertical angles, which means that they must equal each other. So we would then write our equation as 3x+20=4x+10 or 4x+10=3x+20. Then, to combine like terms, we will subtract 3x from both sides, resulting in x+10=20. Then we will subtract 10 from both sides, resulting in x=10.
5 0
3 years ago
Find a and b if the point p(6,0) and Q(3,2) lie on the graph of ax+ by=12
tiny-mole [99]

to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})

\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12

5 0
2 years ago
Determine if the point (4, -3) is a solution
Aneli [31]
Not a solution I believe.
6 0
3 years ago
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