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4 years ago

How are the layers of the atmosphere defined?

1 answer:

8 0

The layers of the atmosphere are defined by variations in temperature and pressure with altitude. These include the troposphere (0 to 16 km), stratosphere (16 to 50 km), mesosphere (50 to 80km) and thermosphere (80 to 640km).

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How many codons are needed to specify 3 amino acids?

Nataliya [291]

There need be 9 amino acids, as each amino acid is composed of 3 codons.
Hope this helps!

5 0

4 years ago

A 5.00g piece of metal is heated to 100.0°C, then placed in a beaker containing 20.0 of water at 10.0°C. The temperature of the

Ahat [919]

Answer:

This metal has a specific heat of 0.9845J/ g °C

Explanation:
Step 1: Given data
q = m*ΔT *Cp
⇒with m = mass of the substance
⇒with ΔT = change in temp = final temperature T2 - initial temperature T1
⇒with Cp = specific heat (Cpwater = 4.184J/g °C) (Cpmetam = TO BE DETERMINED)

Step 2: Calculate specific heat
For this situation : we get for q = m*ΔT *Cp
q(lost, metal) = q(gained, water)

- mass of metal(ΔT)(Cpmetal) = mass of water (ΔT) (Cpwater)
-5 * (15-100)(Cpmetal) = 20* (15-10) * (4.184J/g °C =
-5 * (-85)(Cpmetal) = 418.4

Cpmetal = 418.4 / (-5*-85) = 0.9845 J/g °C

This metal has a specific heat of 0.9845J/ g °C

7 0

3 years ago

According to the kinetic molecular theory, what effect do collisions between gas particles in a sample of an ideal gas have?

elena55 [62]

According to the kinetic theory of gases, the collisions among the molecules are perfectly elastic, that is, when the collision of the molecules takes place, they bounce off each other with no gain or loss of energy. No repulsive or attractive forces take part at the time of collisions, so energy is conserved.

3 0

3 years ago

A sample of gas occupies a volume of 67.1 mL . As it expands, it does 135.3 J of work on its surroundings at a constant pressure

Semmy [17]

Answer:

$V_2=1.363x10^{-3}m^3=1363mL$

Explanation:

Hello,

In this case, since the work done at constant pressure as in isobaric process is computed by:

$W= P(V_2-V_1)$

Thus, given the pressure, initial volume and work, the final volume is:

$V_2=V_1+\frac{W}{P}$

Whereas the pressure must be expressed in Pa as the work is given in J (Pa*m³):

$P=783Torr*\frac{101325Pa}{760Torr} =104394Pa$

And the volumes in m³:

$V_1=67.1mL*\frac{1m^3}{1x10^6mL} =6.71x10^{-5}m^3$

Thus, the final volume turns out:

$V_2=6.71x10^{-5}m^3+\frac{135.3Pa*m^3}{104394Pa}\\\\V_2=1.363x10^{-3}m^3=1363mL$

Best regards.

3 0

4 years ago

Type the correct answer in the box. express your answer to three significant figures. an air mattress is filled with 0.55 moles

dmitriy555 [2]

385 L is the volume of the air mattress with 0.55 moles of air inside the mattress and a temperature of 295 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 3.5 kPa

V=?

n= 0.55 moles of air

T= 295K

R= 8.314 (L kPa/mol K)

Putting value in the given equation:

V= $\frac{nRT}{P}$

V = $\frac{(0.55 moles)(8.314 L kPa/mol k)(295 K)}{3.5 kPa}$

V = 385.4132857 L

And whatever the significant figure is asked for, for example, 3 significant figures: the answer would be 385 litres.

Hence, 385.4132857 L is the volume of the air mattress.

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

5 0

2 years ago