Write the electron configurations of these ions, potassium and magnesium

Specific amino acids that line the selectivity filter of the K channel can dehydrate K and allow passage of that ion but cannot

Bogdan [553]

Answer:

Hi

True

Explanation:

Since on the inner and outer surfaces of the membrane, a series of negatively charged amino acids are found, which increase the local concentration of cations. The path of the ions begins on the inner surface filled with water molecules where the ion can retain its hydration sphere. Two thirds of its interior in the membrane the inside of the channel narrows in the region of the selectivity filter, forcing the ion to separate from the water molecules. Oxygen atoms in the selectivity filter replace the water molecules in the K+ hydration sphere, forming a series of coordination spheres through which the ion moves. The preferential stabilization of K+ against Na+ is the basis of the ion selectivity of this filter.

5 0

2 years ago

Write a chemical equation representing the first ionization energy for lithium. use e− as the symbol for an electron.

just olya [345]

The chemical equation representing the first ionization energy for lithium is given by;

Li → Li + e-

<h2>Further Explanation; </h2><h3>Ionization energy</h3>

Ionization energy is the energy required to remove outermost electrons from the outermost energy level. Energy is required to remove an electron from an atom.
The closer an electron is to the nucleus the more energy is required, since the electron is more tightly bound to the atom thus making it more difficult to remove, hence higher ionization energy.
Ionization energy increases across the periods and decreases down the group from top to bottom.
Additionally, the ionization energy increases with subsequent removal of a second or a third electron.

<h3>First ionization energy </h3>

This is the energy required to remove the first electron from the outermost energy level of an atom.
Energy needed to remove the second electron to form a divalent cation is called the second ionization energy.

<h3>Trends in ionization energy </h3><h3>1. Down the group(top to bottom)</h3>

Ionization energy decreases down the groups in the periodic table from top to bottom.
It is because as you move down the group the number of energy levels increases making the outermost electrons get further from the nucleus reducing the strength of attraction to the nucleus.
This means less energy will be required compared to an atoms of elements at the top of the groups.

<h3>2. Across the period (left to right)</h3>

Ionization energy increases across the period from left to right.
This can be explained by an increase in nuclear energy as extra protons are added to the nucleus across the period increasing the strength of attraction of electrons to the nucleus.
Consequently, more energy is needed to remove electrons from the nucleus.

Keywords: Ionization energy, periodic table, energy levels, electrons

<h3>Learn more about</h3>

Ionization energy: brainly.com/question/1971327
Trend in ionization energy: brainly.com/question/1971327
First ionization energy: brainly.com/question/1971327

Level: High school

Subject: Chemistry

Topic: Periodic table and chemical families

Sub-topic: Ionization energy

4 0

3 years ago

Read 2 more answers

Five kg of carbon dioxide (CO2) gas undergoes a process in a well-insulated piston-cylinder assembly from 2 bar, 280 K to 20 bar

kaheart [24]

This question is incomplete, the complete question is;

Five kg of carbon dioxide (CO2) gas undergoes a process in a well-insulated piston-cylinder assembly from 2 bar, 280 K to 20 bar, 520 K. If the carbon dioxide behaves as an ideal gas, determine the amount of entropy produced, in kJ/K. Assuming;

a) constant specific heats Cp = 0.939 kJ/Kg K

b) variable specific heats

Answer:

a) the amount of entropy produced is 0.731599 kJ/K

b) the amount of entropy produced is 0.69845 kJ/K

Explanation:

Given the data in the question;

5 kg of carbon dioxide (CO₂) gas undergoes a process in a well-insulated piston-cylinder assembly.

m = 5 kg

Molar mass M = 44.01 g/mol

P₁ = 2 bar, P₂ = 20

T₁ = 280 K, P₂ = 520 K

Since its insulated { q = 0 } ( kinetic and potential energy effects = 0 )

Now,

a) the amount of entropy produced, in kJ/K, Assuming constant specific heats with Cp = 0.939 kJ/Kg K

S $_{Generation$ = m × ((Cp × In( T₂/T₁) - R × In( P₂/p₁ ))

we substitute

S $_{Generation$ = 5 × (( 0.939 × In( 520/280) - 0.1889 × In( 20/2 ))

= 5 × ( 0.5812778 - 0.434958 )

= 5 × 0.1463198

= 0.731599 kJ/K

Therefore, the amount of entropy produced is 0.731599 kJ/K

b) the amount of entropy produced, in kJ/K, Assuming variable specific heats.

Now, from Table A-23: Ideal Gas Properties of Selected Gases;

T₁,T₂ : s₁⁰ = 211.376 kJ/kmol-K, s₂⁰ = 236.575 kJ/kmol-K

now, s₁ = s₁⁰ / M and s₂ = s₂⁰ / M

we substitute

s₁ = s₁⁰ / M = 211.376 / 44.01 = 4.8029 kJ/kg

s₂ = s₂⁰ / M = 236.575 / 44.01 = 5.37548 kJ/kg

S $_{Generation$ = m × (( s₂ - s₁ ) - R × In( p₂ / p₁ ))

we substitute

S $_{Generation$ = 5 × (( 5.37548 - 4.8029 ) - 0.1880 × In( 20 / 2 ))

= 5 × ( 0.57258 - 0.432885997 )

= 5 × 0.13969

= 0.69845 kJ/K

Therefore, the amount of entropy produced is 0.69845 kJ/K

5 0

2 years ago

which of the following is the most wasteful use of water? taking a shower rather than a bath watering the garden with recycled w

kvasek [131]

Water running dish washer

5 0

3 years ago

Read 2 more answers

811.68 J of energy are used on a 95g chunk of unknown metal. Calculate the resulting temperature change if the specific heat of

Ivan

Answer:

16 °C

Explanation:

Step 1: Given data

Provided heat (Q): 811.68 J

Mass of the metal (m): 95 g

Specific heat capacity of the metal (c): 0.534 J/g.°C

Step 2: Calculate the temperature change (ΔT) experienced by the metal

We will use the following expression.

Q = c × m × ΔT

ΔT = Q/c × m

ΔT = 811.68 J/(0.534 J/g.°C) × 95 g = 16 °C

6 0

2 years ago