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FinnZ [79.3K]
3 years ago
5

F a particular galaxy has a total mass of 10 to the 58 grams and the average star in that galaxy has a mass of 10 to the 34 gram

s, approximately how many stars are there in that galaxy?
Mathematics
1 answer:
atroni [7]3 years ago
5 0

Answer:

10^{24}=1000,000,000,000,000,000,000,000 stars.

Step-by-step explanation:

We have been given that a particular galaxy has a total mass of 10^{58} grams and the average star in that galaxy has a mass of 10^{34} grams. We are asked to find the number of stats in the galaxy.

To find the number of stats in the given galaxy, we will divide total mass of galaxy by mass of an average star in the galaxy as:

\text{The number of stats in the given galaxy}=\frac{10^{58}}{10^{34}}

Using exponent property \frac{a^m}{a^n}=a^{m-n}, we will get:

\text{The number of stats in the given galaxy}=10^{58-34}\\\\\text{The number of stats in the given galaxy}=10^{24}\\\\\text{The number of stats in the given galaxy}=1000,000,000,000,000,000,000,000

Therefore, there are approximately 1000,000,000,000,000,000,000,000 stars in the given galaxy.

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3 years ago
What percent of 150 is 108?
N76 [4]
X% of 150 = 108

x/100 * 150 = 108

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8 0
3 years ago
Linda read 1/5 of a book on Friday and 2/7 of the book on Saturday. On Sunday she read 5/9 of the remaining pages. What fraction
insens350 [35]
Here, you just want to solve it by finding a common denominator.
1/5+2/7, because she read 1/5 and 2/7 of the book on separate days. The common denominator is 35.
7/35+10/35
=17/35
So that's how much of the book she read before Saturday.
Now it says that on Sunday she read 5/9 of the remaining pages, meaning:
1-17/35 should give us our answer
35/35-17/35=18/35
But since it says she read 5/9 of the remaining pages, we need to multiply 18/35 by 5/9 to get what 5/9ths of 18/35 is.
(18/35)(5/9)=2/7
Therefore she read 2/7ths of the book on Sunday.
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3 years ago
What is the inverse of the given function? y = 7x2 -­ 3. A. B. C. D.
Sergeeva-Olga [200]
Y = 7x^2-3

x=7y^2-3


.......................


8 0
3 years ago
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