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3 years ago

11

The circle below has center H. Suppose that =m∠FHG64°. Find the following.

1 answer:

Tatiana [17]3 years ago

6 0

Answer:

(a) m FG = 64°

(b) m ∠FEG = 32°

Step-by-step explanation:

m∠FHG64° = m FG = 64°

m ∠FEG = 32° is half of m∠FHG64°

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You roll two dice. What is the probability you get a 2 and a number greater than 2?

abruzzese [7]

Hello!

You have to find the probability of getting a 2

This is a 1/6 chance

Then you have to find the chance of getting a number greater than 2

This is a 4/6 chance

To find the chance of these happening at the same time you multiply these together

1/6 * 4/6 = 1/9

There is a 1/9 chance

Hope this helps!

6 0

3 years ago

Read 2 more answers

What is the first step when rewriting y=3x^2+9x-18

Pachacha [2.7K]

Answer:

do the pemdas

p=()

e=X^x

md= multiply then devide

as= add then subtract

Step-by-step explanation:

y=3x^2+9x-18

y=9x+9x-18

18x-18=y

3 0

2 years ago

A 10-foot ladder is leaning against a vertical wall. If the bottom of the ladder is being pulled away from the wall at the rate

Alex777 [14]

Answer:

The area is changing at 15.75 square feet per second.

Step-by-step explanation:

The triangle between the wall, the ground, and the ladder has the following dimensions:

H: is the length of the ladder (hypotenuse) = 10 ft

B: is the distance between the wall and the ladder (base) = 6 ft

L: the length of the wall (height of the triangle) =?

dB/dt = is the variation of the base of the triangle = 9 ft/s

First, we need to find the other side of the triangle:

$H^{2} = B^{2} + L^{2}$

$L = \sqrt{H^{2} - B^{2}} = \sqrt{(10)^{2} - B^{2}} = \sqrt{100 - B^{2}}$

Now, the area (A) of the triangle is:

$A = \frac{BL}{2}$

Hence, the rate of change of the area is given by:

$\frac{dA}{dt} = \frac{1}{2}[L*\frac{dB}{dt} + B\frac{dL}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} + B\frac{d(\sqrt{100 - B^{2}})}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} - \frac{B^{2}}{(\sqrt{100 - B^{2}})}*\frac{dB}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - 6^{2}}*9 - \frac{6^{2}}{\sqrt{100 - 6^{2}}}*9]$

$\frac{dA}{dt} = 15.75 ft^{2}/s$

Therefore, the area is changing at 15.75 square feet per second.

I hope it helps you!

5 0

3 years ago

Does anyone know what to do for this equation? 40 of $2.40= ?

wolverine [178]

Answer:

0.96 or .96

Step-by-step explanation:

40 divided by 100 = 0.4 to change the percent to a decimal

and multiply 2.40 to 0.4, 0.4 times 2.40 is 0.96 or .96

3 0

3 years ago

Please help me with this asap

zysi [14]

Answer:

Upper left is 9, upper right is 9, lower left is 21

Step-by-step explanation:

They tell us there are 9 birds that are yes fly and yes fish, so that’s the upper right.

They tell us there are 18 yes fish total. Subtract the 9 from the upper right, and that leaves 9 for the upper left.

They tell us there are 39 birds total.

39 - 18 (all fish eaters) - 4 (no fly, no fish) = 17 that can fly but don’t eat fish.

Make sense? lmk if you have questions

7 0

3 years ago