Triangle E D F has sides that are of varying lengths. Side E D has a length of 4 and side E F has a length of 9.
2 answers:
Answer:
D E + E F greater-than D F
5 less-than D F less-than 13
Triangle D E F is a scalene triangle
Step-by-step explanation:
we know that
The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side
we have the triangle EDF
where
<u><em>Applying the triangle inequality theorem</em></u>
1)
2)
so
The length of DF is the interval -----> (5,13)
The triangle DEF is a scalene triangle (the three length sides are different)
therefore
<em>The statements that are true are</em>
D E + E F greater-than D F
5 less-than D F less-than 13
Triangle D E F is a scalene triangle
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Solution:
x y ║ z w→→Given
Also, x z is a transversal, that intercepts x y and z w.
So, ∠ x z w=∠z x y→→Alternate interior angles as, x y ║ z w.
Also, v is point of intersection of x z and y w.
∠ x v y ≅ ∠ z v w→→[ Vertically opposite angles]
So,→→ Δ x y v ~ Δ z w v⇒⇒[Angle-Angle Similarity]
