Triangle E D F has sides that are of varying lengths. Side E D has a length of 4 and side E F has a length of 9.
2 answers:
Answer:
D E + E F greater-than D F
5 less-than D F less-than 13
Triangle D E F is a scalene triangle
Step-by-step explanation:
we know that
The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side
we have the triangle EDF
where
<u><em>Applying the triangle inequality theorem</em></u>
1)
2)
so
The length of DF is the interval -----> (5,13)
The triangle DEF is a scalene triangle (the three length sides are different)
therefore
<em>The statements that are true are</em>
D E + E F greater-than D F
5 less-than D F less-than 13
Triangle D E F is a scalene triangle
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Answer with Step-by-step explanation:
Since we have given that
a. f: ℝ → ℝ given by f(x) = x + 2
Domain would be all real numbers i.e. (-∞, ∞)
Range would be all real numbers i.e. (-∞, ∞)
b. g: ℝ → ℝ given by g(x) = √x − 1
Domain would be all positive numbers i.e. [0,∞)
Range would be [-1,∞)
c. f(g(x))
Domain would be [0,∞)
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d. g(f(x))
Domain would be [-2,∞)
Range would be (0,∞)