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NARA [144]
3 years ago
9

Im making this to get a new rank no need to answer answer if you like.

Mathematics
1 answer:
Lena [83]3 years ago
7 0

Answer:

nice

Step-by-step explanation:

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PLS HELP ME ILL MARK BRAINIEST
skad [1K]

Answer:

Question 1- 288.48

Step-by-step explanation:

depending on how they round your answer the number might look different.

V= Bh which means (pi)r^2(h)

3.14 x 1.25^2 x 4.9

V=24.040625 ~ 24.04

12 x 24.04

=288.48

5 0
2 years ago
2.1 If 5 + 3 = 0 and < 0, evaluate (without using a calculator):
Sergeeva-Olga [200]

1. 18

2.8

3.-1

<h3>What is expression?</h3>

An expression is a set of terms combined using the operations +, – , x or ,/.

Given:

1. 22 − 1 (4)

=22- 1*4

= 22-4

= 18

2. 2 + 2 (3)

=2+2*3

=2+6

=8

3. 1 − 2

= -1

Learn more about expression here:

brainly.com/question/14083225

#SPJ1

6 0
2 years ago
Can someone plsss help :)
OLga [1]
Set equal to eachother
(2x+1) = 79
Subtract 1 from both sides
2x=78
Divide 2 from both sides
2x/2=78/2
X= 39
5 0
3 years ago
This is finding exact values of sin theta/2 and tan theta/2. I’m really confused and now don’t have a clue on how to do this, pl
Lostsunrise [7]

First,

tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>)

and given that 90° < <em>θ </em>< 180°, meaning <em>θ</em> lies in the second quadrant, we know that cos(<em>θ</em>) < 0. (We also then know the sign of sin(<em>θ</em>), but that won't be important.)

Dividing each part of the inequality by 2 tells us that 45° < <em>θ</em>/2 < 90°, so the half-angle falls in the first quadrant, which means both cos(<em>θ</em>/2) > 0 and sin(<em>θ</em>/2) > 0.

Now recall the half-angle identities,

cos²(<em>θ</em>/2) = (1 + cos(<em>θ</em>)) / 2

sin²(<em>θ</em>/2) = (1 - cos(<em>θ</em>)) / 2

and taking the positive square roots, we have

cos(<em>θ</em>/2) = √[(1 + cos(<em>θ</em>)) / 2]

sin(<em>θ</em>/2) = √[(1 - cos(<em>θ</em>)) / 2]

Then

tan(<em>θ</em>/2) = sin(<em>θ</em>/2) / cos(<em>θ</em>/2) = √[(1 - cos(<em>θ</em>)) / (1 + cos(<em>θ</em>))]

Notice how we don't need sin(<em>θ</em>) ?

Now, recall the Pythagorean identity:

cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1

Dividing both sides by cos²(<em>θ</em>) gives

1 + tan²(<em>θ</em>) = 1/cos²(<em>θ</em>)

We know cos(<em>θ</em>) is negative, so solve for cos²(<em>θ</em>) and take the negative square root.

cos²(<em>θ</em>) = 1/(1 + tan²(<em>θ</em>))

cos(<em>θ</em>) = - 1/√[1 + tan²(<em>θ</em>)]

Plug in tan(<em>θ</em>) = - 12/5 and solve for cos(<em>θ</em>) :

cos(<em>θ</em>) = - 1/√[1 + (-12/5)²] = - 5/13

Finally, solve for sin(<em>θ</em>/2) and tan(<em>θ</em>/2) :

sin(<em>θ</em>/2) = √[(1 - (- 5/13)) / 2] = 3/√(13)

tan(<em>θ</em>/2) = √[(1 - (- 5/13)) / (1 + (- 5/13))] = 3/2

3 0
2 years ago
What is the estimate of forgive 6in by 4in
NNADVOKAT [17]

Find area of the semi circle.

The diameter is, half of that would be the radius, which is 3.

\frac{\pi \cdot 3^2}{2} = 14.1

Find the area of the rectangle.

6 * 4 =24

Add the two areas together.

24 + 14.1 = 38.1

38.1in^2

6 0
3 years ago
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