43x+2=64+455−766
Step 1: Simplify both sides of the equation.
43x+2=64+455−766
43x+2=64+455+−766
43x+2=(64+455+−766)(Combine Like Terms)
43x+2=−247
43x+2=−247
Step 2: Subtract 2 from both sides.
43x+2−2=−247−2
43x=−249
Step 3: Divide both sides by 43.
43x
/43 = −249
/43
x = −249
/43
Answer:
x = −249
/43
so wt's the question of this pic?
Answer:
x = 10 and x = -2
Step-by-step explanation:
The equation has 2 solutions because we have a square. When things are squares, we get a positive and negative solution.
(x-4)^2 - 28 = 8
Add 28 to each side
(x-4)^2 - 28+28 = 8+28
(x-4)^2 = 36
Take the square root of each side
sqrt((x-4)^2) = ±sqrt(36)
x-4 = ±6
Add 4 to each side
x-4+4 = 4 ±6
x = 4 ±6
x = 4+6 and x = 4-6
x = 10 and x = -2
Answer:
3.
Step-by-step explanation:
This is a geometric series so the sum is:
a1 * r^n - 1 / (r - 1)
= 1 * (2^101 -1) / (2-1)
= 2^101 - 1.
Find the remainder when 2^101 is divided by 7:
Note that 101 = 14*7 + 3 so
2^101 = 2^(7*14 + 3) = 2^3 * (2^14)^7 = 8 * (2^14)^7.
By Fermat's Little Theorem (2^14) ^ 7 = 2^14 mod 7 = 4^7 mod 7.
So 2^101 mod 7 = (8 * 4^7) mod 7
= (8 * 4) mod 7
= 32 mod 7
= 4 = the remainder when 2^101 is divided by 7.
So the remainder when 2^101- 1 is divided by 7 is 4 - 1 = 3..
Answer:
i would love to help but there is no question :(
Step-by-step explanation:
