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liraira [26]
3 years ago
9

Draw a line representing the rise and a line representing the run of the run. State the slope of the line in simplest form.​

Mathematics
2 answers:
ozzi3 years ago
8 0
The slope is 4/3 , 4/3 is the answer
bekas [8.4K]3 years ago
4 0
4/3 is the correct slope of the line :)
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In the equation 6-(2*
ASHA 777 [7]
20=x+10

x=10 would be your answer
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What is the next step in completing this construction?
muminat
The intent of the construction appears to be to produce tangents from point P to the circle O. There are several possible next steps:
• Name the point of intersection just created between the arc and circle O
• Draw a line (or segment) between points P and J
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Can anyone solve this?
UkoKoshka [18]

Answer:

D) 26.04 ft

Step-by-step explanation:

Let's set up a equation with two ratios:

\frac{miniature\ house}{real\ house}=\frac{miniature\ house}{real \ house}

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\frac{1in}{1.55ft}=\frac{16.8in}{x}

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D) 26.04 ft

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3 years ago
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2(x+y)=23-2y <br>6x-7=20-5y​
slavikrds [6]

Answer:

the solution is (-1/2, 6).

Step-by-step explanation:

Next time, please share the instructions.

Start by carrying out the indicated multiplication:

2x + 2y = 23 - 2y

Consolidate l ike terms:  combine 2y and -2y:  result:  +4y on the left side:

2x + 4y = 23

Let's solve this system using elimination by substitution.  Multiply 2x + 4y = 23 by -3 to obtain a -6x term:

-3(2x + 4y = 23) = -6x - 12y = -69.  Now combine this result with the second equation:

-6x - 12y = -69

6x + 5y  = 20 + 7

-------------------------

        - 7y = -42

Dividing both sides by -7, we get y = 6.  Subbing 6 for y in the 2nd equation, we get:

6x = 27 -5(6), or

6x  =  27 - 30 = -3

Then x = -3/6, or x = -1/2

and the solution is (-1/2, 6).

3 0
3 years ago
The faces of a cube are to be numbered with integers 1 through 6 in such a way that consecutive numbers are always on adjacent f
Blizzard [7]

Answer:

Total different ways to number the remaining faces is 10.

Step-by-step explanation:

It is given that consecutive numbers are always on adjacent faces (not opposite ones).

The face numbered 1 is on top and the face numbered 2 is toward the front.

Top = 1

Front = 2

The remaining faces are left right bottom back. Total possibilities are shown below.

S.no.      3                4              5               6

(1)       Right         Back         Bottom       Left  

(2)       Right         Back         Left         Bottom  

(3)       Right        Bottom       Left           Back  

(4)       Right        Bottom       Back         Left  

(5)       Bottom      Right         Back         Left  

(6)       Bottom       Left          Back        Right  

(7)       Left            Back       Bottom       Right  

(8)       Left            Back        Right         Bottom  

(9)       Left           Bottom      Right          Back  

(10)     Left            Bottom      Back         Right

When Bottom=3, then we can not place 4 on back because doing this 5 and 6 are opposite ones.

Therefore, total different ways to number the remaining faces is 10.

7 0
3 years ago
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