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liraira [26]
3 years ago
9

Draw a line representing the rise and a line representing the run of the run. State the slope of the line in simplest form.​

Mathematics
2 answers:
ozzi3 years ago
8 0
The slope is 4/3 , 4/3 is the answer
bekas [8.4K]3 years ago
4 0
4/3 is the correct slope of the line :)
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PLS HELP ME ASAP WITH 42!! (MUST SHOW WORK!!) + LOTS OF POINTS!! *best if show picture with work!!*
ddd [48]
I thought this would be simple, as I'm familiar with algebra and not really "The constant of proportionality," but I will do my best.

So this said "Constant of proportionality," is referring to basically the answers for the equation when X equals certain numbers.

Make a table of different answers when you plug in X and you get the 'Constant of proportionality.'

y = 2.5x + 3
y = 2.5(1) + 3
y = 2.5 + 3
y = 5.5

Since we plugged in 1 for X and got 5.5 for Y, our input and output is (1, 5.5)

Replace X for a different value, and you will get a bunch of different numbers that will in essence be your function inputs and outputs.  Make a table of these and you have your answer.

EXAMPLE - 
-= x =-   -= y =-
-= 1 =-   -= 5.5 =-
-= 2 =-   -= 8 =-
-= 3 =-   -= 11.5 =-
-= 4 =-   -= 13 =-


So there you have it.  I hope this helps!  If you have any further questions, don't hesitate to ask.
3 0
3 years ago
What is the constant of variation for the inverse variation? xy = 8
Advocard [28]

Answer:

  8

Step-by-step explanation:

The constant of variation is the constant in the equation: 8.

___

The equation can be rewritten to be

  y = 8/x

Compared to the generic equation for inverse variation, ...

  y = k/x

we see that the constant of variation (k) is the constant in the given equation, 8.

6 0
3 years ago
When studying radioactive​ material, a nuclear engineer found that over 365​ days, 1,000,000 radioactive atoms decayed to 973 co
HACTEHA [7]

Answer:

A. number of decayed atoms = 73.197

Step-by-step explanation:

In order to find the answer we need to use the radioactive decay equation:

N(t)=N0*e^{kt} where:

N0=initial radioactive atoms

t=time

k=radioactive decay constant

In our case, when t=0 we have 1,000,000 atoms, so:

1,000,000=N0*e^{k*0}

1,000,000=N0

Now we need to find 'k'. Using the provied information that after 365 days we have 973,635 radioactive atoms, we have:

973,635=1,000,000*e^{k*365}

ln(973,635/1,000,000)/365=k

-0.0000732=k

A. atoms decayed in a day:

N(t)=1,000,000*e^{-0.0000732t}

N(1)=1,000,000*e^{-0.0000732*1}

N(1)= 999,926.803

Number of atoms decayed in a day = 1,000,000 - 999,926.803 = 73.197

B. Because 'k' represents the probability of decay, then the probability that on a given day 51 radioactive atoms decayed is k=0.0000732.

4 0
3 years ago
Is AABC a right triangle? How do you know?
Kazeer [188]

Answer:

it would be C because they don't give enough information

5 0
2 years ago
Tell what you would do to isolate the variable. -5c = 5/24
Masteriza [31]

To isolate the variable here is what you would do:

−5c= \frac{5}{24}

Step 1: Divide both sides by -5.

\frac{-5c}{-5} = \frac{5}{24} (A five was supposed to go underneath the 24 to show the division but whatever)

Answer: c=\frac{-1}{24}



8 0
3 years ago
Read 2 more answers
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