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VladimirAG [237]
4 years ago
5

Calculate the kinetic energy in joules of a 10g bullet moving at 300 m/s

Physics
2 answers:
mina [271]4 years ago
8 0
Given: Mass m= 10 g   convert to Kg  m = 0.01 Kg        Velocity  V = 300 m/s

Required: Kinetic energy = K.E = 1/2 mV²

K.E = 1/2 (0.01 Kg)(300 m/s)²

K.E = 450 J
Naily [24]4 years ago
8 0

Answer:

450 J

Explanation:

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A middle-aged man typically has poorer hearing than a middle-aged woman. In one case a woman can just begin to hear a musical to
Dmitriy789 [7]

Answer:

4

Explanation:

I_0 = Threshold intensity for woman

I = Intensity of sound for man

\beta = Intensity level of sound = 6 dB

Intensity level of sound is given by

\beta=10log\dfrac{I}{I_0}\\\Rightarrow 6=10log\dfrac{I}{I_0}\\\Rightarrow \dfrac{6}{10}=log\dfrac{I}{I_0}\\\Rightarrow 10^{\dfrac{6}{10}}=\dfrac{I}{I_0}\\\Rightarrow \dfrac{I}{I_0}=10^{\dfrac{6}{10}}\\\Rightarrow \dfrac{I}{I_0}=10^{0.6}\\\Rightarrow \dfrac{I}{I_0}=3.98\approx 4

The ratio is 4

8 0
4 years ago
Heating effect of current is not always useful for us. Support your answer with example<br>​
stellarik [79]

Answer:

is correct

Explanation:

in my think, first this due to ray emitted from the light those ray may be affect our skin or party of body.

4 0
3 years ago
A proton with a speed of 3.000×105 m/s has a circular orbit just outside a uniformly charged sphere of radius 7.00 cm. What is t
Rama09 [41]

To solve this problem we will apply the principles of energy conservation. The kinetic energy in the object must be maintained and transformed into the potential electrostatic energy. Therefore mathematically

KE = PE

\frac{1}{2} mv^2 = \frac{kq_1q_2}{r}

Here,

m = mass (At this case of the proton)

v = Velocity

k = Coulomb's constant

q_{1,2} = Charge of each object

r= Distance between them

Rearranging to find the second charge we have that

q_2 = \frac{\frac{1}{2} mv^2 r}{kq_1}

Replacing,

q_2 = \frac{\frac{1}{2}(1.67*10^{-27})(3*10^5)^2(7*10^{-2})}{(9*10^9)(1.6*10^{-19})}

q_2 = 3.6531nC

Therefore the charge on the sphere is 3.6531nC

4 0
3 years ago
A 10kg ball has a momentum of 40 kg.m/s. What is the ball’s speed.
Whitepunk [10]

Answer:

<h2>4 m/s</h2>

Explanation:

The speed of the ball can be found by using the formula

s=  \frac{p}{m}  \\

p is the momentum

m is the mass

From the question we have

v =  \frac{40}{10}  = 4 \\

We have the final answer as

<h3>4 m/s</h3>

Hope this helps you

7 0
3 years ago
Find the average braking force of a 1000 kg car moving at 10 m/s braking to a stop in 5 s.
Verdich [7]

Answer:

-2000 N

Explanation:

To solve the problem, we can use the impulse theorem, which states that the impulse is equal to the change in momentum of the car:

I = \Delta p\\F \Delta t = m \Delta v

where

F is the average breaking force

\Delta t = 5 s is the stopping time

m = 1000 kg is the mass of the car

\Delta v = -10 m/s is the change in velocity of the car

Solving the equation for F,

F=\frac{m \Delta v}{\Delta t}=\frac{(1000 kg)(-10 m/s)}{5 s}=-2000 N

5 0
4 years ago
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