FT=MV
F(4)=(5)(20)
F= 100/4
F= 25 N
Answer:
60km/hr due east
Explanation:
Given parameters:
Displacement = 60km East
Start time = 10am
End time = 11am
Unknown:
Average velocity = ?
Solution:
The average velocity is the displacement divided by the time taken.
For this journey, the time taken is;
11am - 10am = 1hr
So;
Average velocity = 
= 60km/hr due east
1). the product of the two masses being gravitationally attracted to each other
2). the distance between their centers of mass
And that's IT. The gravitational force between them depends on
only those two things, nothing else.
An object is thrown horizontally from the open
window of a building. If the initial speed of the
object is 20 m/s and it hits the ground 2.0 s later,
from what height was it thrown? (Neglect air
resistance and assume the ground is level.)
Initial vertical velocity = 0
formula: s = ut + (1/2)*g*t^2
s = 0 + 1/2*9.8*2^2
s = 9.8*2 = 19.6 m
The distance is 28 meters and the direction of displacement is East I think
