Question

Find the average braking force of a 1000 kg car moving at 10 m/s braking to a stop in 5 s.

Answer 1

Answer:

-2000 N

Explanation:

To solve the problem, we can use the impulse theorem, which states that the impulse is equal to the change in momentum of the car:

$I = \Delta p\\F \Delta t = m \Delta v$

where

F is the average breaking force

$\Delta t = 5 s$ is the stopping time

m = 1000 kg is the mass of the car

$\Delta v = -10 m/s$ is the change in velocity of the car

Solving the equation for F,

$F=\frac{m \Delta v}{\Delta t}=\frac{(1000 kg)(-10 m/s)}{5 s}=-2000 N$