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Arte-miy333 [17]
4 years ago
6

Can you solve question about circles

Mathematics
1 answer:
nekit [7.7K]4 years ago
3 0
Yes i can how about u
You might be interested in
How do I do this please help??
Brums [2.3K]

Answer:

Slope: 4

Y-intercept: -5

Equation: y=4x-5

Step-by-step explanation:

Slope formula:

\frac{y2 - y1}{x2 - x1}

So let's use the ordered pairs (1, -1) and (2,3) from the table (it doesnt matter which ones you choose) and plug the numbers in to the formula:

\frac{3 - ( - 1)}{2 - 1}

Which is equal to:

\frac{4}{1}

Which is equal to 4. So the slope is 4.

To find the y-intercept, substitute the slope and an ordered pair into the slope-intercept equation, y=mx+b. So let's use (1,-1).

-1=4(1)+b

= -1=4+b

= -1-4=4-4+b

= -5=b

So the y-intercept is -5.

Then for the equation, you just plug in the slope and the y-intercept into y=mx+b, which would be:

y=4x-5

3 0
4 years ago
Ray BA and BC are opposite rays, and Ray BE bisects
Monica [59]
<span>Ray BE bisects </span>∠ABD.

According to picture, this is the solution. In case the question is complete.
5 0
4 years ago
Computers from a certain manufacturer have a mean lifetime of 62 months, with a standard deviation of 12 months. The distributio
Goryan [66]

Answer:

Between 38 and 86 months.

Step-by-step explanation:

Chebyshev Theorem

The Chebyshev Theorem can also be applied to non-normal distribution. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

An in general terms, the percentage of measures within k standard deviations of the mean is given by 100(1 - \frac{1}{k^{2}}).

In this question:

Mean of 62, standard deviation of 12.

Between what two lifetimes does Chebyshev's Theorem guarantee that we will find at least approximately 75% of the computers?

Within 2 standard deviations of the mean, so:

62 - 2*12 = 38

62 + 2*12 = 86

Between 38 and 86 months.

6 0
3 years ago
What is the equivalent fraction for 35/40
ddd [48]
It's 7/8 ...which is the simplest form of 35/40... Hope it helps !!!
5 0
4 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by
a_sh-v [17]

Answer:

Dimension of the box is 16.1\times 7.1\times 2.45

The volume of the box is 280.05 in³.

Step-by-step explanation:          

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is L=21-2h

The width of the box is W=12-2h

The volume of the box is V=L\times W\times H

V=(21-2h)\times (12-2h)\times h

V=(21-2h)\times (12h-2h^2)

V=252h-42h^2-24h^2+4h^3

V=4h^3-66h^2+252h

To maximize the volume we find derivative of volume and put it to zero.

V'=12h^2-132h+252

0=12h^2-132h+252

Solving by quadratic formula,

h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}

h=\frac{132\pm72.99}{24}

h=2.45,8.54

Now, substitute the value of h in the volume,

V=4h^3-66h^2+252h

When, h=2.45

V=4(2.45)^3-66(2.45)^2+252(2.45)

V\approx 280.05

When, h=8.54

V=4(8.54)^3-66(8.54)^2+252(8.54)

V\approx -170.06

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is L=21-2(2.45)=16.1

The width of the box is W=12-2(2.45)=7.1

So, Dimension of the box is 16.1\times 7.1\times 2.45

6 0
4 years ago
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