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3 years ago

Determine whether the rates of change are constant or variable.

Mathematics

1 answer:

kupik [55]3 years ago

4 0

Answer:

The rates of change are variables.

Step-by-step explanation:

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Fofino [41]

The answer less then 6

8 0

3 years ago

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Can somebody explain to me how they got 3^4(x) = 3^3(x+2)? Then explain what happened to the 3 in 3^4 and the 3 in 3^3? Please a

musickatia [10]

Answer:

x=6

Step-by-step explanation:

81^x = 27 ^(x+2)

81 = 3^4 and 27 =3^3 so replace 81 and 27 in the equation

3^4^x = 3^3^(x+2)

When we have a power to a power we can multiply the exponents

a ^b^c = a^(b*c)

3^(4x) = 3^(3*(x+2))

Since the bases are the same, the exponents have to be the same

a^b = a^c means b=c

4x = 3(x+2)

Now we can solve for x

Distribute

4x = 3x+6

Subtract 3x from each side

4x-3x = 3x-3x+6

x = 6

3 0

4 years ago

What is the slope intercept form of the equation 2y+3x=-8

antoniya [11.8K]

Answer:

y=-1.5x-4

Step-by-step explanation:

Slope intercept form is y=mx+b

Bring x over to the other side

2y=-8-3x

divide by 2

y=-4-1.5x

y=-1.5x-4 should be your equation in slope-intercept form

8 0

2 years ago

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Hays builds model sailboats as a hobby. the dimensions of the sailboats are given. what is the height, x, of the smaller sailboa

Solnce55 [7]

7/8=x/12
Answer is 10.5

6 0

3 years ago

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Jane is playing a game in which he spins a spinner with 6 equal-sized slices numbered 1 through 6. The spinner stops on a number

sleet_krkn [62]

Answer:

The expected value of playing the game is $0.75.

Step-by-step explanation:

The expected value of a random variable is the weighted average of the random variable.

The formula to compute the expected value of a random variable X is:

$E(X)=\sum x\cdot P(X=x)$

The random variable X in this case can be defined as the amount won in playing the game.

The probability distribution of X is as follows:

Number on spinner: 1 2 3 4 5 6

Amount earned (X): $1 $4 $7 $10 -$8.75 -$8.75

Probability: 1/6 1/6 1/6 1/6 1/6 1/6

Compute the expected value of X as follows:

$E(X)=\sum x\cdot P(X=x)$

$=(1\times \frac{1}{6})+(4\times \frac{1}{6})+(7\times \frac{1}{6})+(10\times \frac{1}{6})+(-8.75\times \frac{1}{6})+(-8.75\times \frac{1}{6})$

$=\frac{1}{6}+\frac{4}{6}+\frac{7}{6}+\frac{10}{6}-\frac{8.75}{6}-\frac{8.75}{6}$

$=\frac{1+4+7+10-8.75-8.75}{6}$

$=0.75$

Thus, the expected value of playing the game is $0.75.

5 0

3 years ago