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Brilliant_brown [7]

3 years ago

9

The table shows data for a random sample of 20 students out of middle school. Use the sample to draw an inference about each mea

sure. Explain your reasoning.

1 answer:

Grace [21]3 years ago

6 0

Im not sure counfused

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Add the equations.<br> 3x - y = -1<br> - 3x + 3y= 27

harkovskaia [24]

Step-by-step explanation:

3x - 3x -y + 3y = 27-1

2y = 26

y = 13 use this to find the value of x

3x - 13 = -1

3x = -1 + 13

3x = 12

x = 4

3 0

4 years ago

How many hours are in 3:30-8?

aleksandrvk [35]

4 hours and 30 Minutes

-y$∞

3 0

4 years ago

At NC State University, 16.4% of the undergraduate classes have more than 50 students. If a random sample of 200 undergraduate c

Lena [83]

Answer:

We need to check the conditions in order to use the normal approximation.

$np=200*0.164=32.8 \geq 10$

$n(1-p)=200*(1-0.164)=167.2 \geq 10$

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$p =0.164$

And the deviation is given by:

$\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262$

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=200, p=0.164)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We need to check the conditions in order to use the normal approximation.

$np=200*0.164=32.8 \geq 10$

$n(1-p)=200*(1-0.164)=167.2 \geq 10$

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$p =0.164$

And the deviation is given by:

$\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262$

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

6 0

3 years ago

Find the product. (–5k + 5)(–5k2 + 2k – 8)

boyakko [2]

Answer:

25 K³ - 35k²+ 50 K - 40

===========================================

Step-by-step explanation:

Given that :

(-5k + 5)(-5k² + 2k - 8)

= -5K (-5k² + 2k - 8) + 5 (-5k² + 2k - 8)

= 25 K³ - 10k² + 40 K - 25 K² + 10 K - 40

= 25 K³ - 35k²+ 50 K - 40

<u>So, the product = 25 K³ - 35k²+ 50 K - 40</u>

5 0

3 years ago

George drove 240 miles to his grandmother's house. The graph below shows the relationship between the distance he traveled and t

Igoryamba

Answer:

I think it's <u><em>A</em></u>

Step-by-step explanation:

8 0

4 years ago