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zvonat [6]
3 years ago
5

E line plot below shows the amount of water Rickayla drinks in 10 days. Part a: how many cups of water did Rickayla drink in 10

days?
Mathematics
1 answer:
Levart [38]3 years ago
6 0

Answer:

Total = 23\frac{1}{4} cups

Step-by-step explanation:

Incomplete question.

See attachment for line plot

Required

Total cups drank in 10 days

The number of x at the top of each dataset represent the frequency (i.e. number of cups) drank on that day.

To get the total, we simply multiply this frequency by the accompanying dataset.

So, we have:

Total = 2 * 1\frac{1}{2} + 1 * 1\frac{3}{4} + 2 * 2 + 2 * 2\frac{3}{4} + 3 * 3

Express fractions as improper fraction

Total = 2 * \frac{3}{2} + 1 * \frac{7}{4} + 2 * 2 + 2 * \frac{11}{4} + 3 * 3

Evaluate each product

Total = 3 + \frac{7}{4} + 4 + \frac{11}{2} + 9

Take LCM

Total = \frac{12+ 7+16+22+36}{4}

Total = \frac{93}{4}

Total = 23\frac{1}{4}

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Answer:

D) 0 = 2(x + 5)(x + 3)

Step-by-step explanation:

Which of the following quadratic equations has no solution?

We have to solve the Quadratic equation for all the options in other to get a positive value as a solution for x.

A) 0 = −2(x − 5)2 + 3

0 = -2(x - 5) × 5

0 = (-2x + 10) × 5

0 = -10x + 50

10x = 50

x = 50/10

x = 5

Option A has a solution of 5

B) 0 = −2(x − 5)(x + 3)

Take each of the factors and equate them to zero

-2 = 0

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x - 5 = 0

x = 5

x + 3 = 0

x = -3

Option B has a solution by one of its factors as a positive value of 5

C) 0 = 2(x − 5)2 + 3

0 = 2(x - 5) × 5

0 = (2x -10) × 5

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Option C has a solution of 5

D) 0 = 2(x + 5)(x + 3)

Take each of the factors and equate to zero

0 = 2

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For option D, all the values of x are 0, or negative values of -5 and -3.

Therefore the Quadratic Equation for option D has no solution.

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