Y = kx where k is a constant
27 = k*9
k = 27/9 = 3
required variation is y = 3x
Answer:
10
Step-by-step explanation:
just do 4-18 and u get the answer
Lines that are parallel have the same slope, and the given line (y = 6x - 5) has a slope of 6; we are looking for a line with a slope of 6.
To form an equation for a line, you need to know the y-intercept (the point at which the line intersects the y-axis). The first step to finding the y-intercept is to plot the given point. After you've done that, count six units up (this is our slope) and one to the right; plot the point. Lastly, draw the line by connecting the points and see where the line intersects the y-axis.
My graph shows that the line intersects the y-axis at -17. All that's left now is to put our information together into an equation. I'm assuming the problem wants the equation in slope-intercept form; slope-intercept form is y = mx + b where m is the slope and b is the y-intercept, so it would look like this:
y = 6x -17
Hope this helps.
For parts A, B, C, and D you most likely created a line. What question E is asking is for you to create a line that is perpendicular to the line you already created that also passes through the point (1,1). What is important to understand here is that the slope of the perpendicular line is the negative reciprocal of the original line's slope... if the original slope is (-4/3) than the perpendicular slope is (3/4)... then you should just plug that new slope into point-slope form or slope-intercept form to get your equation... y-y1 = m(x-x1) ... y-1= (3/4)(x-1) ... so it would be y=(3/4)x + 1/4 then for part f just convert into standard form which is just manipulating the variables... look up standard form equation on Google and manipulate the variables from there.
