Answer: 60 miles
Step-by-step explanation:
Given
It takes ferry 2 hours to travel to town A and only
to travel back to town B.
Speed of current is 
Suppose the speed of the ferry is
mph
Distance traveled in both the cases is same, but it took more time traveling to city A that is, ferry is moving upstream and downstream for returning time.

Distance between the towns is 
Answer:
solution is
[-3,-1]
Step-by-step explanation:
we are given

Firstly, we will find critical values
so, let's assume it is equal

now, we can break absolute sign
For
:

we can solve for x

Add both sides by 20


Divide both sides by -10
and we get

For
:

we can solve for x

Subtract both sides by 20


Divide both sides by 10
and we get

so, critical values are


now, we can draw a number line and locate these values
and then we can check inequality on each intervals
For
:
We can select any random value from this interval and plug that in inequality
and we get
we can plug x=-5



so, this is FALSE
For
:
We can select any random value from this interval and plug that in inequality
and we get
we can plug x=-2



so, this is TRUE
For
:
We can select any random value from this interval and plug that in inequality
and we get
we can plug x=0



so, this is FALSE
so, solution is
[-3,-1]
Answer: m = 11
Step-by-step explanation: Isolate the variable by dividing each side by facotrs that don't contain the variable.
Hope this helps you out! ☺
Answer:
12.
Step-by-step explanation:
Replace k in the radical by -2:
So we have √(-72*-2)
= √144
= 12.
Answer:
330
Step-by-step explanation:
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