One form of the equation of a parabola is
y = ax² + bx + c
The curve passes through (0,-6), (-1,-12) and (3,0). Therefore
c = - 6 (1)
a - b + c = -12 (2)
9a + 3b + c = 0 (3)
Substitute (1) into (2) and into (3).
a - b -6 = -12
a - b = -6 (4)
9a + 3b - 6 = 0
9a + 3b = 6 (5)
Substitute a = b - 6 from (4) into (5).
9(b - 6) + 3b = 6
12b - 54 = 6
12b = 60
b = 5
a = b - 6 = -1
The equation is
y = -x² + 5x - 6
Let us use completing the square to write the equation in standard form for a parabola.
y = -[x² - 5x] - 6
= -[ (x - 2.5)² - 2.5²] - 6
= -(x - 2.5)² + 6.25 - 6
y = -(x - 2.5)² + 0.25
This is the standdard form of the equation for the parabola.
The vertex us at (2.5, 0.25).
The axis of symmetry is x = 2.5
Because the leading coefficient is -1 (negative), the curve opens downward.
The graph is shown below.
Answer: y = -(x - 2.5)² + 0.25
The correct answer for this question is " y=x, x-axis, y=x, y-axis." The <span>set of reflections that would carry hexagon ABCDEF onto itself is that first, let y = x. Then it will be followed by the x-axis. Then do same thing as the first, y = x. Then do the y-axis part.</span>
Answer:
{π/4, 5π/4}
Step-by-step explanation:
Tan theta -1=0 could be rewritten as tan Ф = 1. The tangent function is 1 at Ф = π/4. As the period of the tangent function is π,
tan Ф = 1 will be true for Ф = π/4 + π, or (5/4)π.
The solution set is {π/4, 5π/4}.
idk what kind of math problem but, if its just simple id us PEMDAS