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3 years ago

How are you all my friends?

Mathematics

2 answers:

ladessa [460]3 years ago

4 0

Answer:

good

Step-by-step explanation:

Muhammad was born around 570, AD in Mecca (now in Saudi Arabia). His father died before he was born and he was raised first by his grandfather and then his uncle. He belonged to a poor

artcher [175]3 years ago

3 0

Hello

What's up?

I hope you are well and fine

Have a Great day ahead

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Sierra has plotted two vertices of a rectangle at (3,2) and (8,2). What is the length of the sides of the rectangle

Eddi Din [679]

Answer:

5units

Step-by-step explanation:

Given the two vertices of a rectangle at (3,2) and (8,2). We are to calculate the distance between the two points.

Using the formula

D = √(x2-x1)²+(y2-y1)²

D = √(2-2)²+(8-3)²

D = √0+5²

D = √25

D = 5

Hence the length of the side of the rectangle is 5units

4 0

2 years ago

lbvjy [14]

In similar triangles ratios of corresponding sides are constant, so

|AB|/|DE| = |BC|/|EF|

5/10 = 8/|EF|

|EF| = (8*10)/5 = 16

|EF| = 16

6 0

2 years ago

15. Which answer choice contains all the factors of 10? A. 1, 10 B. 1, 2, 5, 10 C. 1, 2, 5 D. 2, 5

nikitadnepr [17]

B. 1, 2, 5, 10 (To feel space)

7 0

3 years ago

Read 2 more answers

What is the output of the function f(x) = x + 21 if the input is 4? When the input is 4, the output of f(x) = x + 21 is

notka56 [123]

To find the output when you know the input, just plug the input into the function.

x+21=4+21=25

The output is 25.

Hope this helps!

8 0

3 years ago

Read 2 more answers

A sphere of radius r is cut by a plane h units above the equator, where

Anika [276]

Consider the top half of a sphere centered at the origin with radius $r$ , which can be described by the equation

$z=\sqrt{r^2-x^2-y^2}$

and consider a plane

$z=h$

with $0$ . Call the region between the two surfaces $R$ . The volume of $R$ is given by the triple integral

$\displaystyle\iiint_R\mathrm dV=\int_{-\sqrt{r^2-h^2}}^{\sqrt{r^2-h^2}}\int_{-\sqrt{r^2-h^2-x^2}}^{\sqrt{r^2-h^2-x^2}}\int_h^{\sqrt{r^2-x^2-y^2}}\mathrm dz\,\mathrm dy\,\mathrm dx$

Converting to polar coordinates will help make this computation easier. Set

$\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\var\phi\end{cases}\implies\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi$

Now, the volume can be computed with the integral

$\displaystyle\iiint_R\mathrm dV=\int_0^{2\pi}\int_0^{\arctan\frac{\sqrt{r^2-h^2}}h}\int_{h\sec\varphi}^r\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$

You should get

$\dfrac{2\pi}3\left(r^3\arctan\dfrac{\sqrt{r^2-h^2}}h-\dfrac{h^3}2\left(\dfrac{r\sqrt{r^2-h^2}}{h^2}+\ln\dfrac{r+\sqrt{r^2-h^2}}h\right)\right)$

5 0

3 years ago

How are you all my friends?​

How are you all my friends?