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soldi70 [24.7K]
3 years ago
9

Solve the equation. j-5 =3.4

Mathematics
2 answers:
dimaraw [331]3 years ago
7 0
It’s 8.4 because if you add 3.4+5 it will give you the solution
never [62]3 years ago
6 0

Answer:1.6

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Ok so we are in quadrant 2, that means sine is positive while cosine is negative.

We are given \cos(\theta)=\frac{-2}{3}(\frac{\text{adjacent}}{\text{hypotenuse}}).

So to find the opposite we will just use the Pythagorean Theorem.

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Now to find \csc(\theta) and \tan(\theta).

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Some teachers do not like the radical on bottom so we will rationalize the denominator by multiplying the numerator and denominator by sqrt(5).

So \csc(\theta)=\frac{3}{\sqrt{5}} \cdot \frac{\sqrt{5}}{\sqrt{5}}=\frac{3 \sqrt{5}}{5}.

And now \tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}=\frac{\sqrt{5}}{-2}=\frac{-\sqrt{5}}{2}.

So we have \csc(\theta)=\frac{3 \sqrt{5}}{5} \text{ and } \tan(\theta)=\frac{-\sqrt{5}}{2}.

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Step-by-step explanation:

hope this answer will help you

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A+ B = 30. A:B what is equivalent to 2:3
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