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3 years ago

The formula for the area of a triangle is . Solve for b. Explain

Mathematics

1 answer:

barxatty [35]3 years ago

5 0

Answer:

the formula for the area of a triangle is a= b*h/2

Step-by-step explanation:

area= base* height divided by two.

if a triangles base was 5 height was 4 the area would be 10units

5*4=20

20/2=10

I used a random example as the specific example was not listed in the question.

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Aleks04 [339]

Answer:

Step-by-step explanation: is the answer

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3 years ago

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Write 8 * 10^-7 in standard form 8*10^-7 =____

tino4ka555 [31]

Answer:

0.0000008

Step-by-step explanation:

Given

8*10^-7

Converted to standard form

8*10^-7 = 8*0.0000001 = 0.0000008

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3 years ago

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Move the slider on the graph on the right to graph each function:

DedPeter [7]

Answer:

The domain is $x\geq 7$

The range is $y\geq 1$

Step-by-step explanation:

we have

$y=\sqrt{x-7} +1$

Find the domain

Remember that

The domain of a function is the set of all possible values of x

we know that the radicand of the function must be greater than or equal to zero

$x-7\geq 0$

solve for x

$x\geq 7$

therefore

The domain is $x\geq 7$

Find the range

Remember that

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

For x=7

The value of y is equal to

$y=\sqrt{7-7} +1=1$

The solution for y is the interval [1,∞)

therefore

The range is $y\geq 1$

6 0

3 years ago

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A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a

sdas [7]

Answer:

$y=-\dfrac{13}{49}x^2$

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

$y=ax^2+bx+c$

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

$-13=a(-7)^2+b(-7)+c$

$49a-7b+c=-13$

(x,y) = (7,-13)

$-13=a(7)^2+b(7)+c$

$49a+7b+c=-13$

(x,y) = (0,0)

$0=a(0)^2+b(7)+c$

$c=0$

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

$49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13$

$49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13$

we can solve these two equation using the elimination method, by simply adding the two equations

$\quad\quad49a-7b=-13\\+\quad49a+7b=-13$

------------------------------

$\quad\quad 98a=-26$

$\quad\quad a=-\dfrac{13}{49}$

Now we can plug this value of a in any of the two equations.

$49a-7b=-13$

$49\left(-\dfrac{13}{49}\right)-7b=-13$

$-13-7b=-13$

$-7b=0$

$b=0$

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

$y=\left(-\dfrac{13}{49}\right)x^2+0x+0$

$y=-\dfrac{13}{49}x^2$

$49y=-13x^2$

This our equation of the arch!

5 0

3 years ago

5x – 19 <1 OR - 4x + 3 < -6 Solve for x

astra-53 [7]

Answer:

x < 4

x > - 2.25

= 4 > x > - 2.25

Step-by-step explanation:

5x - 19 < 1

5x < 1 + 19

5x < 20

x < 20/5

x < 4

- 4x + 3 < - 6

- 4x < - 6 - 3

- 4x < - 9

x > 9/- 4

x > - 2.25

7 0

3 years ago