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Art [367]
2 years ago
11

I don't understand this question at all please help if you do

Mathematics
1 answer:
lorasvet [3.4K]2 years ago
7 0

Answer:

Answer is \frac{4}{3}

Step-by-step explanation:

To find the interval of x. Use our equations to equal each other.

-x^2+2x=y,y=0

-x^2+2x=0\\-x(x-2)=0\\-x=0 , (x-2)=0\\x=0 ,2

\int\limits^2_0 {-x^2+2x} \, dx

Integrate.

\frac{-x^3}{3}+x^2\\(\frac{-2^3}{3}+2^2)-[\frac{-0^3}{3}+0^2]\\-\frac{8}{3} +4-0\\-\frac{8}{3}+\frac{12}{3}  =4/3

Using Desmos I have Graphs of both of the equations you have provided. The problem asks us to find the shaded region between those curves/equations.

Proof Check your interval of x.

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Use a double angle identity to rewrite the formula r(Θ)=<img src="https://tex.z-dn.net/?f=1%2F16v%5E2sin%28theta%29cos%28theta%2
Artist 52 [7]

Answer:

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Step-by-step explanation:

Given the expression r(theta) = 1/16v²sinθcosθ

According to double angle of trigonometry identity;

Sin2θ = sin(θ+θ)

Sin2θ = sinθcosθ + cosθsinθ

Sin2θ = 2sinθcosθ

sinθcosθ = sin2θ/2 ... **

Substituting equation ** into the question

1/16v²sinθcosθ = 1/16v²(sin2θ/2)

1/16v²sinθcosθ = 1/2×1/16v²(sin2θ)

1/16v²sinθcosθ = 1/32v²sin2θ

Hence using the double angle identity, the equivalent expression is 1/32v²sin2θ

7 0
3 years ago
This Quarter circle has a radius of 7 cm
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3 years ago
3-4z = -5+8z Can someone help?
noname [10]
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3 0
3 years ago
Read 2 more answers
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