(4,4) are the coordinates of C prime
If y = √(2x + 1), then differentiating both sides implicitly with respect to t gives
dy/dt = 1/2 • 1/√(2x + 1) • 2 • dx/dt = 1/√(2x + 1) • dx/dt
(a) If dx/dt = 9 and x = 4, then
dy/dt = 1/√(2•4 + 1) • 9
dy/dt = 1/√(8 + 1) • 9
dy/dt = 1/√9 • 9
dy/dt = 9/3
dy/dt = 3
(b) If dy/dt = 3 and x = 40, then
3 = 1/√(2•40 + 1) • dx/dt
3 = 1/√(80 + 1) • dx/dt
3 = 1/√81 • dx/dt
3 = 1/9 • dx/dt
dx/dt = 27
Answer:
Step-by-step explanation:
Solve the given 3x + 5y = 2 for y. This will automatically indicate the slope of the line.
Subtracting 3x from both sides of this equation, we get:
5y = -3x = -3x + 2.
Dividing both sides by 5 yields y = (-3/5)x + 2/5.
The slope of the given line is -3/5. The y-intercept of this line is (0, 2/5).
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What is it that I am supposed to be doing?
Hello!
Okay, so first we need to add like terms... so first, add the terms with the same variables. That gives us:
9x + 7y + 4 + y
Now add 7y and y
That gives us:
9x + 8y + 4
This can't be added anymore... this is as far as we can go because they are no longer like terms.