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2 years ago

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Solve the rational equation quantity 3 times x minus 5 end quantity divided by 7 equals four sevenths. A: f(n) = f(n − 1) ⋅ 0.3

+ 25, n > 0 B: f(n) = 100 − f(n − 1) ⋅ 0.3 + 25, n > 0 C: f(n) = f(n − 1) ⋅ 0.7 + 25, n > 0 D:f(n) = 100 − f(n − 1) ⋅ 0.7 + 25, n > 0

1 answer:

KengaRu [80]2 years ago

4 0

Answer:

2.8 < x -0

Step-by-step explanation:

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Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

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3 years ago

The ball used in a soccer game may not weigh more than 16 ounces or less

Liono4ka [1.6K]

In order for the ball to be used in the game, it must be able to meet the minimum and maximum weight requirements. These are the limits of the weight of the ball. If it exceeds the maximum limit of 16 ounces or below the minimum limit of 14 ounces, the ball will not be approved.

So, by adding 1.5 ounces, that would mean that the initial weight of the ball did not reach the minimum limit. The initial weight of the ball, denoted as x, have two possible values. The first value is the initial weight plus added with 1.5 ounces would reach 14 ounces.

x + 1.5 = 14
x = 12.5 ounces

The other scenario is when the initial weight is added to reach the maximum requirement of 16 ounces

x + 1.5 = 16
x = 14.5 ounces

From both answer, we could conclude that the initial weight has to be 12.5 ounces. If the initial weight were 14.5 ounces to begin with, there should be no need for air. It cans till be approved to be used.

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3 years ago

How do you solve this using a picture and the work?

hoa [83]

Okkk so u need to use the Pythagorean Theorum.
$a x^{2} +b x^{2} =c x^{2}$

a=x
b=1
c=5

so...
$c x^{2} -b x^{2} =a x^{2}$

$5 x^{2} -1 x^{2} =a x^{2}$

Solve that

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3 years ago

The equation of a circle is (X+12)^2+(y+16)^2=r^2, and the circle passes through the origin. The equation of the circle then cha

serious [3.7K]

Answer:

$x=\sqrt{r_{2} +y-16(r2-y+16)+30}$ R2

$r=\sqrt{x^2+24x+y2+32y+400}$

Step-by-step explanation:

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3 years ago

A hot tub pump circulates 3.9 cubic feet of water per minute.how many cubic inches of water does it circulate each second

Basile [38]

Answer:

0.78 cubic inches/sec

Step-by-step explanation:

you take 3.9 cubic feet and multiply it by 12 to convert it into inches and you get 46.8 cubic inches. then you divide by 60 to convert minutes to second and you get 0.78. hope that helps

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3 years ago

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