Answer:
X=9 and Y=8
Step-by-step explanation:
In relation BC is only 1 unit more than EF. So following that take AC=10, then subtract 1. Get X=9. Then take DE=7 and add 1. Get Y=8
Answer:
x = 0, x = -4, and x = 6
Step-by-step explanation:
To find the zeros of this polynomial, we can begin by factoring out a common factor of each term. 'x' is a common factor. We can distribute this variable out, giving us:
f(x) = x(x²- 2x- 24)
Now, factor the polynomial inside of the parenthesis into its simplest form. Factors of -24 that add up to -2 are -4 and 6.
f(x) = x( x + 4) (x - 6)
From this, we can derive the zeros x = 0, x = -4 and x = 6.
It’s 6
since it’s right at 5 & 7
Answer:
0.07
Step-by-step explanation:
to find the IQR you do Q3-Q1
2.00-1.93
The question is incomplete. Here is the complete question.
m∠J and m∠Kare base angles of an isosceles trapezoid JKLM.
If m∠J = 18x + 8, and m∠M = 11x + 15 , find m∠K.
A. 1
B. 154
C. 77
D. 26
Answer: B. m∠K = 154
Step-by-step explanation: <u>Isosceles</u> <u>trapezoid</u> is a parallelogram with two parallel sides, called Base, and two non-parallel sides that have the same measure.
Related to internal angles, angles of the base are equal and opposite angles are supplementary.
In trapezoid JKLM, m∠J and m∠M are base angles, so they are equal:
18x + 8 = 11x + 15
7x = 7
x = 1
Now, m∠K is opposite so, they are supplementary, which means their sum results in 180°:
m∠J = 18(1) + 8
m∠J = 26
m∠K + m∠J = 180
m∠K + 26 = 180
m∠K = 154
The angle m∠K is 154°
