Answer:
<em>72,000cm³</em>
Step-by-step explanation:
Volume of the rectangular tank = Length * Width * Height
Given
Length = 50cm
Width = 30cm
Height = 60cm
Get the volume:
Volume = 50*30*60
Volume = 90,000cm³
Hence the volume of the rectangular tank is 90,000cm³.
If 1/5 of the volume of water was transferred to another tank, the volume transferred will be:
Amount transferred = 1/5 * 90,000
Amount transferred = 18000cm³
Amount left in the tank = 90,000 - 18,000
<em>Amount of water left in the tank = 72,000cm³</em>
34% of the scores lie between 433 and 523.
Solution:
Given data:
Mean (μ) = 433
Standard deviation (σ) = 90
<u>Empirical rule to determine the percent:</u>
(1) About 68% of all the values lie within 1 standard deviation of the mean.
(2) About 95% of all the values lie within 2 standard deviations of the mean.
(3) About 99.7% of all the values lie within 3 standard deviations of the mean.



Z lies between o and 1.
P(433 < x < 523) = P(0 < Z < 1)
μ = 433 and μ + σ = 433 + 90 = 523
Using empirical rule, about 68% of all the values lie within 1 standard deviation of the mean.
i. e. 
Here μ to μ + σ = 
Hence 34% of the scores lie between 433 and 523.
Answer:
The simplified form of the given expression is (2x-1).
Step-by-step explanation:
Consider the given expression is

According to the Inverse Properties of In

In the given expression the power of e is (2x-1).
Using the Inverse Properties of In, we get

Therefore, the simplified form of the given expression is (2x-1).