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kirza4 [7]
2 years ago
10

What is an equation of the line that is parallel to y = 9- 4x and passes through (0, 7)​

Mathematics
1 answer:
kkurt [141]2 years ago
3 0

Answer:

y = -4x + 7

Step-by-step explanation:

Since they are parallel they must have the same gradient which is -4

y = mx + c

m = -4

x = 0

y = 7

7 = -4 × 0 + c

c = 7

y =  - 4x + 7

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The answer oils be 2 square root 2 because 4 times 2 is 8 and because the square root of 4 is 2 you would move that 2 to the outside and keep the other two on the inside of the square root.
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To simplify the following expression, which operation would you complete second?
Bingel [31]
Divide, the first operation is the parentheses and then division
3 0
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Point Z is the circumcenter of ΔTUV.
Vsevolod [243]

Answer:

32.8

Step-by-step explanation:

Since the angles given are 90 degrees and 57.2 you can add those together then subtract them from 180 to find the answer 32.8.

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7 0
3 years ago
Read 2 more answers
Segments
Kazeer [188]

Given

AB  and  CD  intersect

AC,  CB,  BD  and  AD  are congruent.

Prove that AB  is the bisector of ∠CAD and ray  CD  is the bisector of ∠ACB.

and AB  and  CD  are perpendicular.

To proof

Bisector

<em>A bisector is that which cut an angle in two equal parts.</em>

In ΔACB and ΔADB

AD = AC  ( Given )

AB = AB   ( common )

BC = DB  ( Given )

by SSS congurence property

we have

ΔACB ≅ΔADB

∠CAB =∠ DAB

∠CBA = ∠DBA

( By corresponding sides of the congurent triangle )

Thus AB is the bisector of the ∠CAD.

InΔ DAC and ΔDBC

AD = DB (Given)

AC = CB  ( Given )

CD = CD (common)

By SSS congurence property

ΔDAC≅ Δ DBC

∠  ACD =∠ BCD

∠ADC =∠BDC

( By corresponding sides of the congurent triangle )

Therefore CD is the bisector of the CAD.

In ΔBOC andΔ BOD

BO = BO ( Common )

∠BCO = ∠BDO

( As prove above ΔACB ≅ΔADB

Thus ∠ACB = ∠ADB by corresponding sides of the congurent triangle , CD is a bisector

∠BCO = ∠BDO )

 CB = DB ( given )

by SAS congurence property

ΔBOC ≅ ΔBOD

∠BOC =∠ BOD

∠BOC +∠ BOD = 180 °( Linear pair )

2∠ BOC = 180°

∠BOC = 90°

∠BOC =∠ BOD = 90°

also

In ΔCOA and ΔAOD

AO = AO ( Common )

∠ACO =∠ ADO

(  As prove above ΔACB ≅ΔADB Thus ACB = ADB by corresponding sides of congurent triangle ,CD is a bisector

thus  ∠ACO = ∠ADO )

AC =AD ( given )

by SAS congurence property

Δ COA ≅ ΔAOD

∠AOC = ∠AOD

( By corresponding angle of corresponding sides )

∠AOC + ∠AOD = 180°

2∠ AOC = 180°   ( Linear pair )

∠AOC = 90°

∠AOC = ∠AOD = 90 °

Thus AB  and  CD  are perpendicular.

Hence proved









   


 



6 0
3 years ago
Diego is 165 cm tall. Andre is 1.7 m tall. Who is taller, Diego or Andre? 1 m = 100 cm.
mart [117]

Answer:

Diego

Step-by-step explanation:

Diego is because 1m = 100 and Diego is 165 and that is alote bigger from 1.7.

8 0
3 years ago
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