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Lemur [1.5K]
3 years ago
15

in the year 2000, there were 5000 living in the town of clairmont. by 2010, the pouplotion had grown to 5600.what is the percent

change in the pouploatian from 2000 to 2010
Mathematics
2 answers:
Orlov [11]3 years ago
8 0
(5600-5,000)/5,000=600/5,000=0.12
0.12* 100% =12

The percent of change is 12% it means that the number of people increases by 12% from the original number of 5,000 in year 2000
Makovka662 [10]3 years ago
5 0
The percent change is 12% increas
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tangare [24]

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60.4 degrees

Step-by-step explanation:

Complementary angles are 2 angles that add up to the sum of 90 degrees.

90-29.6=60.4 degrees

Hope this helps!

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Can anyone please work out question 10 in the picture and clearly explain it? Would appreciate it
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9945/ 39= 255
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alexgriva [62]

Answer:

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Step-by-step explanation:

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base area = radius^2 x 3.14 = 3.65^2 x 3.14 = 41.83265 cm^2

3) find the height of the cylinder:

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It is desired to compare the hourly rate of an entry-level job in two fast-food chains. Eight locations for each chain are rando
notka56 [123]

Answer:

It can be concluded that at 5% significance level that there is no difference in the amount paid by chain A and chain B for the job under consideration

Step by Step Solution:

The given data are;

Chain A 4.25, 4.75, 3.80, 4.50, 3.90, 5.00, 4.00, 3.80

Chain B 4.60, 4.65, 3.85, 4.00, 4.80, 4.00, 4.50, 3.65

Using the functions of Microsoft Excel, we get;

The mean hourly rate for fast-food Chain A, \overline x_1 = 4.25

The standard deviation hourly rate for fast-food Chain A, s₁ = 0.457478

The mean hourly rate for fast-food Chain B, \overline x_2 = 4.25625

The standard deviation hourly rate for fast-food Chain B, s₂ = 0.429649

The significance level, α = 5%

The null hypothesis, H₀:  \overline x_1 = \overline x_2

The alternative hypothesis, Hₐ:  \overline x_1 ≠ \overline x_2

The pooled variance, S_p^2, is given as follows;

S_p^2 = \dfrac{s_1^2 \cdot (n_1 - 1) + s_2^2\cdot (n_2-1)}{(n_1 - 1)+ (n_2 -1)}

Therefore, we have;

S_p^2 = \dfrac{0.457478^2 \cdot (8 - 1) + 0.429649^2\cdot (8-1)}{(8 - 1)+ (8 -1)} \approx 0.19682

The test statistic is given as follows;

t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{S_{p}^{2} \cdot \left(\dfrac{1 }{n_{1}}+\dfrac{1}{n_{2}}\right)}}

Therefore, we have;

t=\dfrac{(4.25-4.25625)}{\sqrt{0.19682 \times \left(\dfrac{1 }{8}+\dfrac{1}{8}\right)}} \approx -0.028176

The degrees of freedom, df = n₁ + n₂ - 2 = 8 + 8 - 2 = 14

At 5% significance level, the critical t = 2.145

Therefore, given that the absolute value of the test statistic is less than the critical 't', we fail to reject the null hypothesis and it can be concluded that at 5% significance level that chain A pays the same as chain B for the job under consideration

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Answer:

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