The answer is the one on the top
Answer:
DE = 20units
Step-by-step explanation:
In Δ ABC,
angle A is congruent to angle B.... (given)
therefore, ΔABC is an isoceles triangle.
therefore, CA = CB..... (side opposite to congruent angles are congruent in an isoceles triangle)
therefore, CB = 4 units
In ΔCDE,
angle D is congruent to angle E.... (given)
therefore, ΔCDE is an isoceles triangle.
therefore, CD = CE
therefore, CD = 8 units
ΔCDE ~ ΔCBA
therefore,

Since it's a right triangle, we can use SOH-CAH-TOA. So tan(x) = opposite/adjacent = 5/20
tan(x) = 1/4 = 0.25
x = arc-tan (0.25) = 14.04°
The answer to 6 is repeating I believe