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Rzqust [24]
3 years ago
11

Write an equation for each problem. Then solve.

Mathematics
1 answer:
Nana76 [90]3 years ago
4 0

Answer:

<em>The price is the same at both stores for 2 prints.</em>

Step-by-step explanation:

<u>Equations</u>

Let's set the variable

x = number of photo prints

Company Photo Plus charges $2 for each print and $6 for a processing fee, thus the total charges are:

PP = 6 + 2x

Company Picture Time charges $3 for each print and $4 for a processing fee, thus it charges a total of:

PT = 4 + 3x

It's required to find the number of prints that make both stores charge the same. Equating both functions:

6 + 2x = 4 + 3x

Subtracting 2x and 4:

x = 2

The price is the same at both stores for 2 prints.

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Find the value of x.
ehidna [41]

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x = 25

Step-by-step explanation:

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6 0
3 years ago
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Dwayne drove 18 miles to the airport to pick up his father and then returned home. On the return trip he was able to drive an av
Nesterboy [21]

Answer:

30 mph

Step-by-step explanation:

Let d = distance (in miles)

Let t = time (in hours)

Let v = average speed driving <u>to</u> the airport (in mph)

⇒ v + 15 = average speed driving <u>from</u> the airport (in mph)

Using:  distance = speed x time

\implies t=\dfrac{d}{v}

Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:

\implies t=\dfrac{18}{v}  \ \ \textsf{and} \ \  t=\dfrac{18}{v+15}

We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:

\implies \dfrac{18}{v} +\dfrac{18}{v+15}=1

Now all we have to do is solve the equation for v:

\implies \dfrac{18(v+15)}{v(v+15)} +\dfrac{18v}{v(v+15)}=1

\implies \dfrac{18(v+15)+18v}{v(v+15)}=1

\implies 18(v+15)+18v=v(v+15)

\implies 18v+270+18v=v^2+15v

\implies v^2-21v-270=0

\implies (v-30)(v+9)=0

\implies v=30, v=-9

As v is positive, v = 30 only

So the average speed driving to the airport was 30 mph

(and the average speed driving from the airport was 45 mph)

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2 years ago
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