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ollegr [7]
3 years ago
14

n 2000 the population of a small village was 2,400. With an annual growth rate of approximately 1.68%, compounded continuously,

what will the population be in 2020 according to the exponential growth function? Round your answer to the nearest whole number, and do not include the units in your answer.
Mathematics
1 answer:
Nitella [24]3 years ago
6 0

Answer:

The population would be 3358

Step-by-step explanation:

Since, exponential growth function if the growth is compound continuously,

A = Pe^{rt}

Where,

P = initial population,

r = growth rate per period,

t = number of periods,

Given,

The population in 2000, P = 2,400,

Growth rate per year = 1.68% = 0.0168,

Number of years from 2000 to 2020, t = 20,

Thus, the population in 2020,

A=2400 e^{0.0168\times 20}

=2400 e^{0.336}

= 3358.4136

\approx 3358

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Step-by-step explanation:

By definition, a relation is a function if and only if each input value has one and only one output value.

For this exercise it is important to remember that thw "Input values"  are the values of the variable "x"and the "Output values"  are the values of the variable"y".

In this case you have the following function provided in the exercise:

y = x^4 - 2x^3 + x^2 + 4x - 10

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3 years ago
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3 years ago
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SOVA2 [1]

Answer:

The correct order is:

a

c

d

b

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Now we assume that 1/x is rational (we want to prove that this implies that x will be also rational and because we know that x is irrational assuming that 1/x is rational will lead to an incongruence), then:

c. If 1/x is rational, then 1/x = p/q for some integers p and q with q ≠ 0. Observe that p is not 0 either, because 1/x is not 0.

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