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andrew-mc [135]
2 years ago
8

Becky says that when she simplifies the following expression, the value is 6 less than her age. What is Becky's age? (7+11) - 8÷

2
20
14
26
11
Mathematics
1 answer:
Hitman42 [59]2 years ago
6 0
(7+11) is 18, (8/2) is 4, 18-4 is 14! If this expression is 6 less than her age, she would be 20!
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I need help on these questions
Kay [80]
1.) 10c - 12 = -2
-2C is the temperature in Tallahassee

2.) 48 kilometers divided the average of 3.2 Km
48÷3.2=15
15 is the value of D

3.) You seem to have 3 =D

4.) I'm pretty sure you just add \frac{1}{4} +  \frac{1}{3} =  \frac{7}{12}
7/12 is your answer

----------------------------------------------------------------------------------------------------------------
Thank You! Have a great day =D
and please correct me if wrong =D
7 0
3 years ago
I'm blanking on how to do this, I learned it so long ago, any help would be greatly appreciated. More interested on how to do it
anyanavicka [17]

Answer:

\dfrac{16 y^{22}}{x^{10}z^{10}}

Step-by-step explanation:

Given expression is ,

\sf\longrightarrow \bigg(\dfrac{2x^3y^{-5}z^8}{8x^{-2}y^6z^3}\bigg)^{-2}

This would be simplified using the law of exponents , some of which I will use here are ,

  • (an)^m = a^m n^m
  • \dfrac{a^m}{a^n}=a^{m-n}

  • a^m a^n = a^{m+n}
  • a^{-n} = \dfrac{1}{a^n}

Using the above laws ,

\sf \longrightarrow \bigg[ \dfrac{2}{8} \bigg(\dfrac{x^3}{x^{-2}}\bigg)\bigg(\dfrac{y^{-5}}{y^6}\bigg)\bigg(\dfrac{z^8}{z^3}\bigg)  \bigg]^{-2}

Using the second law mentioned above , we have,

\sf \longrightarrow \bigg[ \dfrac{1}{4}(x^{3+2})(y^{-5-6})(z^{8-3})\bigg]^{-2}

Simplify ,

\sf \longrightarrow \bigg[\dfrac{1}{4} x^5y^{-11}z^5\bigg]^{-2}

Using the first law mentioned above , we have,

\sf \longrightarrow \bigg[ \dfrac{1}{4^{-2}} x^{5(-2)} y^{-11(-2)} z^{5(-2)}\bigg]

Simplify,

\sf \longrightarrow 4^2x^{-10}y^{22} z^{-10}

Finally using the fourth law mentioned above , we have ,

\sf \longrightarrow \boxed{\bf \dfrac{16 y^{22}}{x^{10}z^{10}}}

<h3>Option K is the correct answer.</h3>
4 0
2 years ago
-11.16 write as a fraction
serious [3.7K]
First lets take away the negative sign for now
Now lets separate the number into its two components which are 11 and 0.16
Now lets rewrite it to 16/100
Next we want to find the greatest common factor between 16 and 100 which is 4 since 4 * 4 equals 16 and 4 * 25 equals 100 so its 4.
Now lets divide 16 and 100 by the greatest common factor so its sixteen divided by 4 over 100 divided by 4
Next we simplify all together which is 4/25
You remember that number 11 we had earlier, well we are going to go grab him back and add him to the fraction and make it 11 4/25 but... remember that negative sign, I said for now, right, so lets put him back on the spotlight.

Answer: -11 4/25
5 0
4 years ago
Please help I have less then 6 minutes
Sonja [21]

Answer:

11) 60°

12) 50°

13) 50°

14) 50°    (i suspect you want ∠FED instead, which is 102°)(NOT a repeat of ∠FDE)

Step-by-step explanation:

6 0
3 years ago
Tiles (6" by 6") can be installed at the rate of 50 per worker hour. The floor of a large lobby area (80’ by 40’) is to be cover
RideAnS [48]

Answer:

Step-by-step explanation:

Tiles (6" by 6") can be installed at the rate of 50 per worker hour. Since the tile is a square, its area is

L^2 = 6^2 = 36 inches square

So in an hour, a worker installs 50 tiles whose area is 36 inches square. Total square meters installed per hour will be 50 × 36 = 1800 inches square per hour.

If three workers are assigned to this task, their work rate will be

1800 × 3 = 5400 inches square per hour.

The floor of a large lobby area (80’ by 40’) is to be covered with these tiles. We would convert from feet to inches.

1 foot = 12 inches

80 feet = 80 × 12 = 960 inches

40 feet = 40 × 12 = 480 inches

Area of the lobby = 90 × 480 = 460800 inches square.

If the 3 workers install 5400 inches square in 1 hour,

Then then they will install 460800 inches square in

460800/5400 = 85.33 hours

Converting to the nearest whole day, it becomes

85.33/24 = 3.55

Approximately 4 days

4 0
3 years ago
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