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3 years ago

HELP QUICK which function has the greater rate of change

Mathematics

1 answer:

kati45 [8]3 years ago

5 0

Answer:

Function A i think.....

Step-by-step explanation:

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The polygons below are similar. Find the value of z.

sveta [45]

The value of "z" equals 8

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3 years ago

X/7=21 what is the answer

Tems11 [23]

<span>here is the answer x = -147

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5 0

3 years ago

Read 2 more answers

Water is pumped into a tank at a rate of r (t)=30(1−e− 0.16t) gallons per minute, where t is the number of minutes since the pum

Vlad1618 [11]

Answer:

The total volume of the water in the tank after 20 minutes = 1220 gallons

Step-by-step explanation:

Rate of water pumped into the tank r (t) = 30 (1 - $e^{-0.16 t}$ )

Initial volume of water in the tank = 800 gallons

The water in the tank after 20 minutes = Initial volume of water in the tank + Volume of water being pumped in the tank

$V_{total} = V_{i} + V_{pump}$

$V_{pump}$ = $\int\limits^a_b {r(t)} \, dt$

Where a = 0 , b = 20

Put the value of r (t) in above equation we get

$V_{pump}$ = $\int\limits^a_b {30 (1 - e^{-0.16t} )} \, dt$

$V_{pump}$ = $30 [ t + \frac{e^{-0.16t} }{0.16} ]$

$V_{pump}$ = $30[ (20- 0) + \frac{1}{0.16}(e^{-0.16 (20)}- e^{0} )$

$V_{pump}$ = 420 gallon

Now, total volume in the tank

$V_{total} = V_{i} + V_{pump}$

$V_{total} = 800 + 420$

$V_{total} = 1220 \ gallon$

Therefore the total volume of the water in the tank after 20 minutes = 1220 gallons

3 0

3 years ago

What is the surface area of the cylinder?

LenaWriter [7]

Answer:

D. 578pi

Step-by-step explanation:

Sorry if that's wrong

7 0

3 years ago

Please answer this question now

Alexeev081 [22]

Answer:

$Area = 400.4 m^2$

Step-by-step Explanation:

Given:

∆UVW,

m < U = 33°

m < V = 113°

VW = u = 29 m

Required:

Area of ∆UVW

Solution:

Find side length UV using Law of Sines

$\frac{u}{sin(U)} = \frac{w}{sin(W)}$

U = 33°

u = VW = 29 m

W = 180 - (33+113) = 34°

w = UV = ?

$\frac{29}{sin(33)} = \frac{w}{sin(34)}$

Cross multiply

$29*sin(34) = w*sin(33)$

Divide both sides by sin(33) to make w the subject of formula

$\frac{29*sin(34)}{sin(33)} = \frac{w*sin(33)}{sin(33)}$

$\frac{29*sin(34)}{sin(33)} = w$

$29.77 = w$

$UV = w = 30 m$ (rounded to nearest whole number)

Find the area of ∆UVW using the formula,

$area = \frac{1}{2}*u*w*sin(V)$

$= \frac{1}{2}*29*30*sin(113)$

$= \frac{29*30*sin(113)}{2}$

$Area = 400.4 m^2$ (to nearest tenth).

4 0

3 years ago