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olga nikolaevna [1]
3 years ago
11

A triangle has vertices at (2, 3), (-2, 2), and (-5,3). What are the coordinates of the vertices of the image

Mathematics
1 answer:
nekit [7.7K]3 years ago
3 0

Answer:

(6,0) (2,-1) (-1,0)

Step-by-step explanation:

just take the coordinates and add 4 and subtract 3 from them.

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Which is smaller,two-thirds of 27 or two-fifths of 20?
shtirl [24]
" of " means multiply

2/3(27) = 54/3 = 18
2/5(20) = 40/5 = 8

so 2/5 of 20 is smaller
7 0
3 years ago
Find the length and width of a rectangle that has the given area and a minimum perimeter. Area: 162 square feet
Gnom [1K]

Answer:

The width and length of rectangle is 12.728 m

Step-by-step explanation:

Let the length of the rectangle = L

let the width of the rectangle = W

The subjective function is given by;

F(p) = 2(L + W)

F = 2L + 2W

Area of the rectangle is given by;

A = LW

LW = 162 ft²

L = 162 / W

Substitute in the value of L into subjective function;

f = 2l + 2w\\\\f = 2(\frac{162}{w} )+2w\\\\f = \frac{324}{w} + 2w\\\\\frac{df}{dw} = \frac{-324}{w^2} +2\\\\

Take the second derivative of the function, to check if it will given a minimum perimeter

\frac{d^2f}{dw^2}= \frac{648}{w^3} \\\\Thus, \frac{d^2f}{dw^2}>0, \ since,\frac{648}{w^3} >0 \ (minimum \ function \ verified)

Determine the critical points of the first derivative;

df/dw = 0

\frac{-324}{w^2} +2 = 0\\\\-324 + 2w^2=0\\\\2w^2 = 324\\\\w^2 = \frac{324}{2} \\\\w^2 = 162\\\\w= \sqrt{162}\\\\w = 12.728 \ m

L = 162 / 12.728

L = 12.728 m

Therefore, the width and length of rectangle is 12.728 m

3 0
2 years ago
What is the least common denominator of 1/3 and 5/6
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The following answer to this equation is LCD = 24
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What is 240 divided by 6 using a double number line?
VMariaS [17]

Answer:

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Step-by-step explanation:

You have to divid 240 by 6

5 0
3 years ago
Can someone help me understand and solve this? Plz...
valentinak56 [21]
320-70= 250
250X1/2=125
X=125
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3 years ago
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