Complete question :
The temperature at 5:00 a.m. was –6 °F. By 3:00 p.m., the temperature had risen to a high of 36 °F. If the temperature at 8:00 p.m. decreased from the high by the change in temperature in Fahrenheit degrees from 5:00 a.m. to 3:00 p.m., what was the temperature at 8:00 p.m.?
Answer:
-6°F
Step-by-step explanation:
Temperature at 5am (t1) = - 6°F
Temperature at 3pm (t2) = 36°F
Change in temperature, between 5am and 3pm:
(t2 - t1) = (36 - (-6)) = (36 + 6) = 42°F
Hence, temperature at 8:00 pm:
High temperature - change in temperature between (5am - 3pm)
36°F - 42°F = - 6°F
Answer:
Step-by-step explanation:
Divide both sides by -3:
For this case we can raise a rule of three based on Anthony trotting 
miles in 23 minutes.
miles -----------> 23 minutes
x ----------------------------------------> 1minute
ANswer:
0.5 miles per minute
