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4 years ago

(5^3)^6 in index form

Mathematics

1 answer:

frozen [14]4 years ago

6 0

Answer:

5^18

Step-by-step explanation:

Multiply 6 and 3 together.

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What number is 25% of 540

dybincka [34]

25%of 540
25/100 ×540
135

6 0

3 years ago

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M–[(m–n)÷(−2)](−5), if m=−4, n=−6

Marrrta [24]

$- 4 - (( - 4 + 6) \div ( - 2))( - 5) = \\ = - 4 - (2 \div ( - 2))( - 5) = \\ = - 4 - ( - 1)( - 5) = - 4 - 5 = \\ = - 9$

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3 years ago

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Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

5 0

3 years ago

Find the intersection point between the lines of equations:<br><br>2x-y+6=0 and 2x+3y-6=0

Ugo [173]

Step-by-step explanation:

The two equation will intersect each other at the point which will be the solution of the given two equations , and the given equations are ,

$\implies 2x -y +6=0\\\\\implies 2x + 3y -6=0$

On subtracting the given equations we have,

$\implies -y - 3y +6 -(-6) = 0 \\\\\implies -4y = -12 \\\\\implies y = -12/-4\\\\\implies y = 3$

Put this value in any equation , we have ,

$\implies 2x -3 +6 =0\\\\\implies 2x = -3 \\\\\implies x =\dfrac{-3}{2} \\\\\implies x =-1.5$

Hence the lines will Intersect at ,

$\implies\underline{\underline{ Point=(-1.5, 3)}}$

8 0

3 years ago

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I don’t get this can someone explain this

LekaFEV [45]

Answer:

15.7 units

Step-by-step explanation:

AB = 6, BC = 3

Therefore by Pythagoras theorem

AC = $\sqrt{45}$

$perimeter \: of \: \triangle \: ABC \\ = 6 + 3 + \sqrt{45} \\ = 9 + 6.70820393 \\ = 9 + 6.7 \\ = 15.7\: units$

3 0

3 years ago