(5^3)^6 in index form

Mathematics

1 answer:

frozen [14]3 years ago

6 0

Answer:

5^18

Step-by-step explanation:

Multiply 6 and 3 together.

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Solve the equation for h? X=r-h/y

Troyanec [42]

Answer:

h = yX -yr

Step-by-step explanation:

X=r-h/y

X - r = h/y

y*(X-r) = h

h = yX -yr

4 0

2 years ago

A container contains water at temperature 80 degree celcius. After every 10 minutes, the change in temperature is - 4 degree cel

lilavasa [31]

For this case, the first thing we must do is define variables.
We have then:
x: number of minutes
y: final temperature
We write then the equation that models the problem:
$y = (-4/10) x + 80
$
For y = 20 we have:
$20 = (-4/10) x + 80
$
Clearing x:
$(4/10) x = 80 - 20

x = (10/4) * 60

x = 150$
Answer:
The temperature of the water will be 20 degree celcius after 150 minutes

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3 years ago

Find the midpoint of the line segment with the endpoints A and B.<br> A(10,6); B(8,4)

MatroZZZ [7]

Answer:

(9,5)

Step-by-step explanation:

10+8/2=18/2=9

6+4/2=10/2=5

4 0

2 years ago

Solve for x. enter your answer in interval notation using grouping symbols. x^2+15x<-36

Oliga [24]

X²+15x+36<0

at first solve quadratic equation

D=b²-4ac= 225-4*1*36= 81

x=(-b+/-√D)/2a
x=(-15+/-√81)/2= (-15+/-9)/2
x1=(-15-9)/2=-12
x2=(-15+9)/2=-3

we can write x²+15x+36<0 as (x+12)(x+3)<0

(x+12)(x+3)<0 can be 2 cases, because for product to be negative one factor should be negative , and second factor should be positive
1 case) x+12<0, and x+3>0,
x<-12, and x>-3
(-∞, -12) and(-3,∞) gives empty set

or second case) x+12>0 and x+3<0
x>-12 and x<-3
(-12,∞) and (-∞,-3) they are crossing , so (-12, -3) is a solution of this inequality

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3 years ago

Find the slope of the line passing through the points (8,-3) and (4,-1)

docker41 [41]

$\rm \to m = \dfrac{y_2 - y_1}{x_2 - x_1}$