(5^3)^6 in index form

Help please with his if you don't mind!!!!!

FrozenT [24]

Job one pays more. the rate is 18.75

7 0

2 years ago

Please help I need to finish my homework

valina [46]

Answer:

AB= 0.625 units (3 s.f.)

∠BAC= 52.9° (1 d.p.)

∠ABC= 32.1° (1 d.p.)

Step-by-step explanation:

Please see the attached pictures for full solution.

- Find AB using cosine rule

- find ∠BAC using sine rule

- find ∠ABC using angle sum of triangle property

4 0

3 years ago

Which of these is an irrational number?

Ilia_Sergeevich [38]

Answer:

$\sqrt{15}$

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find the second partial derivatives of the following functions

artcher [175]

(a) z = 3x ² - 4xy + 15y ²

has first-order partial derivatives

∂z/∂x = 6x - 4y

∂z/∂y = -4x + 30y

and thus second-order partial derivatives

∂²z/∂x ² = 6

∂²z/∂x∂y = -4

∂²z/∂y∂x = -4

∂²z/∂y ² = 30

where ∂²z/∂x∂y = ∂/∂x [∂z/∂y] and ∂²z/∂y∂x = ∂/∂y [∂z/∂x].

(b) z = 4x eʸ

∂z/∂x = 4eʸ

∂z/∂y = 4x eʸ

∂²z/∂x ² = 0

∂²z/∂x∂y = 4eʸ

∂²z/∂y∂x = 4eʸ

∂²z/∂y ² = 4x eʸ

(c) z = 6x ln(y)

∂z/∂x = 6 ln(y)

∂z/∂y = 6x/y

∂²z/∂x ² = 0

∂²z/∂x∂y = 6/y

∂²z/∂y∂x = 6/y

∂²z/∂y ² = -6x/y ²

6 0

2 years ago

A car initially traveling at 20 kilometers per hour takes 10 seconds to speed up to 70 km/hour. At what rate is it changing spee

Snezhnost [94]

Initial velocity=u=20km/h
Final velocity=v=70km/h
Time=10s=t

Convert speeds to m/s

$\\ \rm\longmapsto u=20\times\dfrac{5}{18}=5.05m/s$

$\\ \rm\longmapsto v=70\times \dfrac{5}{18}=19.4m/s$

$\boxed{\sf Acceleration=\dfrac{v-u}{t}}$

$\\ \rm\longmapsto Acceleration=\dfrac{19.4-5.05}{10}$

$\\ \rm\longmapsto Acceleration=\dfrac{14.3}{10}$

$\\ \rm\longmapsto Acceleration=143m/s^2$

7 0

2 years ago