<span>60
Sorry, but the value of 150 you entered is incorrect. So let's find the correct value.
The first thing to do is determine how large the Jefferson High School parking lot was originally. You could do that by adding up the area of 3 regions. They would be a 75x300 ft rectangle, a 75x165 ft rectangle, and a 75x75 ft square. But I'm lazy and another way to calculate that area is take the area of the (300+75)x(165+75) ft square (the sum of the old parking lot plus the area covered by the school) and subtract 300x165 (the area of the school). So
(300+75)x(165+75) - 300x165 = 375x240 - 300x165 = 90000 - 49500 = 40500
So the old parking lot covers 40500 square feet. Since we want to double the area, the area that we'll get from the expansion will also be 40500 square feet. So let's setup an equation for that:
(375+x)(240+x)-90000 = 40500
The values of 375, 240, and 90000 were gotten from the length and width of the old area covered and one of the intermediate results we calculated when we figured out the area of the old parking lot. Let's expand the equation:
(375+x)(240+x)-90000 = 40500
x^2 + 375x + 240x + 90000 - 90000 = 40500
x^2 + 615x = 40500
x^2 + 615x - 40500 = 0
Now we have a normal quadratic equation. Let's use the quadratic formula to find its roots. They are: -675 and 60. Obviously they didn't shrink the area by 675 feet in both dimensions, so we can toss that root out. And the value of 60 makes sense. So the old parking lot was expanded by 60 feet in both dimensions.</span>
Answer:
it's a whole number
Step-by-step explanation:
it's a whole number
It is around 1.81 kilograms
Answer:
The correct option is D ....
Step-by-step explanation:
Angle is ending at the point = (-3, -4)
Signs of both x and y are negative therefore it is in the third quadrant.
To find the the tangent of an angle we have to find the ratio of the length of the opposite side to the length of the adjacent side.
In this question the opposite side of the angle is of 4 units and the adjacent side of the angle is 3 units.
tanθ = y/x
tanθ = -4/-3
tanθ = 4/3
Thus the correct option is D ....
Answer:
the average weight of one peach is 6.4 ounces
Step-by-step explanation:
10lb of peaches
16 ounces in a pound
10 x 16 = 160 ounces
divide 160 (ounces) by 25 (Peaches)
= 6.4 ounces per peach
